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3 years ago

Cameron classified -18/3 as real, rational, integer and a whole number and a whole number. Is he correct? why or why not?

Mathematics

1 answer:

DiKsa [7]3 years ago

6 0

Yes he is correct because -18/3 would turn into -6 a whole number

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2+5.67890654321678-5432

8_murik_8 [283]

-5,424.3 ...............

7 0

3 years ago

A store sells small notebooks for $7 and large notebooks for $10 if a student buys 6 notebooks and spends $51 how many of each s

Finger [1]

He bought 3 small notebooks (3*7=21) and 3 large notebooks (3*10=30)
21+30=51

5 0

3 years ago

Read 2 more answers

Nancy's garden has the dimensions shown 4 1/2 yard<br><br> 3 3/4 yd . She need find the area

Marina86 [1]

Answer:

The area of Nancy's garden is $16\frac{7}{8}\ yd^{2}$

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

$4\frac{1}{2}\ yd=\frac{4*2+1}{2}=\frac{9}{2}\ yd$

$3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd$

Therefore

The area is equal to

$A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}$

convert to mixed number

$\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}$

4 0

3 years ago

25000 rounded to the nearest ten thousand

kozerog [31]

Answer:

30000

Step-by-step explanation:

You round up because it is 5 or < making the 5 a 0 and the 2 a 3. Bringing in the extra 0's makes it 30,000

3 0

3 years ago

Read 2 more answers

What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC

marta [7]

Answer:

C. $B(x,y) = \left(3,-\frac{16}{3} \right)$

Step-by-step explanation:

Let $A(x,y) = (6,-7)$ , $B(x,y) = (x,y)$ and $C(x,y) = (-3,-2)$ . From statement we know that $AB = \frac{1}{2}\cdot BC$ , which is equivalent to the following linear algebraic formula:

$B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)]$ (1)

$B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)$

$\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)$

$B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y)$ (2)

Then, the coordinates of point B on AC are:

$B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)$

$B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)$

$B(x,y) = \left(3,-\frac{16}{3} \right)$

Which means that correct answer is C.

5 0

3 years ago