A.exclusive it’s not an intense level of distribution
In a decision to either sell as is or process a product further, joint costs are considered irrelevant and process further costs are considered relevant.
The decision of whether to sell the product right away or wait to sell it in order to earn more money. Although we think that growing the business's income is great, we also need to make sure that the costs associated with the growth will be met. We must contrast the profit margin between selling now and selling later because additional processes will demand more resources and expenses.
Additionally, we need to make an effort to maximise the return on our investment. Additional processes might need more money spent on equipment. These factors require us to apply the sell or process further technique in order to choose the best course of action.
Typically, this scenario occurs in a joint product where one or more outputs can be generated and produce additional revenue. The joint products are produced at the same cost up until the point where they are divided and further sold or processed. Although the products can be sold at the split point, there are instances when continuing developing them is more profitable.
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Beginning balance 10000
Add service on account 50000
Less ending balance 12000
Received from customers
10,000+50,000−12,000=48,000
Hope it helps!
<span>n/2 = average number of items to search.
Or more precisely (n+1)/2
I could just assert that the answer is n/2, but instead I'll prove it. Since each item has the same probability of being searched for, I'll simulate performing n searches on a list of n items and then calculate the average length of the searches. So I'll have 1 search with a length of 1, another search looks at 2, next search is 3, and so forth and so on until I have the nth search looking at n items. The total number of items looked at for those n searches will be:
1 + 2 + 3 + 4 + ... + n
Now if you want to find the sum of numbers from 1 to n, the formula turns out to be n(n+1)/2
And of course, the average will be that sum divided by n. So we have (n(n+1)/2)/n = (n+1)/2 = n/2 + 1/2
Most people will ignore that constant figure of 1/2 and simply say that if you're doing a linear search of an unsorted list, on average, you'll have to look at half of the list.</span>
Answer:
the answer is D hope that helps you out
