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3 years ago

If I spend 135 dollars and tax is 7 cents per dollar how much would be tax

Mathematics

2 answers:

-Dominant- [34]3 years ago

4 0

IDK but it might be 19?

Leto [7]3 years ago

3 0

Answer:

$229.50

Step-by-step explanation:

You find 7 % of the price then add the answer u get for that to the subtotal

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The students in Ms. Lorenzo’s class collected the following numbers of bottle caps:

gladu [14]

I am not sure how to show you how to do a dot plot on this website, but to see how to do a dot plot

b) Put everything in order and find the middle
10, 10, 10, 20, 30, 30, 30, 30, 40, 50, 50, 50, 60, 60, 70, 70, 2040
^^
So 40 is in the middle, making it the median

c) Add all of the values together and divide by the total number of values.
10 + 10 + 10 + 20 + 30 + 30 + 30 + 30 + 40 + 50 + 50 + 50 + 60 + 60 + 70 + 70 + 2040 = 2660
2660 / 17 = 156.5

5 0

3 years ago

The area of a playground is 266 yd. The width of the playground is 5 yd longer than its length. Find th

Mademuasel [1]

Answer:

Step-by-step explanation:

The width is 5 yds longer so we can mark out b and d if you multiply 19 and 24 is 456 so you are left with C

5 0

3 years ago

Vector u has initial point at (3, 9) and terminal point at (–7, 5). Vector v has initial point at (1, –4) and terminal point at

spin [16.1K]

Answer:

⟨-5, -1⟩

Step-by-step explanation:

Vector:

A vector is given by its endpoint subtracted by its initial point.

Vector u has initial point at (3, 9) and terminal point at (–7, 5)

Then

$u = (-7, 5) - (3,9) = (-7 - 3, 5 - 9) = (-10,-4)$

Vector v has initial point at (1, –4) and terminal point at (6, –1).

Then

$v = (6,-1) - (1,-4) = (6-1,-1-(-4)) = (5,3)$

What is u + v in component form?

$u + v = (-10,-4) + (5,3) = (-10+5,-4+3) = (-5,-1)$

⟨-5, -1⟩ is the answer.

3 0

2 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$