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NNADVOKAT [17]
3 years ago
6

A football team lost 5 yards on one play and gained 12 yards on the next play. Find the overall change in field position.

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

Equation: -5 + 12

Overall change: 7 yards

Step-by-step explanation:

In the problem, it says "lost 5 yards". "Lost" is another way of saying subtraction or negative. Therefore, our starting number is -5.

The problem also says "gained 12 yards". "Gained" is another was of saying addition or positive. Therefore, our second number is positive 12.

Together, these two numbers look like this: -5 + 12. To add them, go 12 to the right of -5 if on a number line. That would be like this: -5, -4, -3, -2, -1, 0, etc until you get to 7 which should be 12 more than -5.

Therefore, the answer is 7 yards.

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17x-3y=4 2x-4y=1 the solution to the system of equations is
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ANSWER

x=\frac{13}{62}

and


y= \frac{-9}{62}e have



EXPLANATION




17x-3y=4---(1)


2x-4y=1



Let us make y the subject and call it equation (2)


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We put equation (2) in to equation (1)




17(\frac{1}{2}+2y)-3y=4


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34y-3y=4- \frac{17}{2}


Simplify to get,



31y= \frac{8-17}{2}



31y= \frac{-9}{2}


Divide both sides by 31,



y= \frac{-9}{2} \div 31



y= \frac{-9}{2} \times \frac{1}{31}




y= \frac{-9}{62}


We put this value in to equation (2) to get,



x=\frac{1}{2}+2\times -\frac{9}{62}




x=\frac{1}{2} -\frac{18}{62}


We collect LCM to obtain,



x=\frac{31-18}{62}



x=\frac{13}{62}








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