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storchak [24]
2 years ago
5

Please help this homework is due today pleaseeee helppp meeeee​

Mathematics
2 answers:
Lelechka [254]2 years ago
8 0
It would be a rotation. if u did any of the other options it sousing line up correctly
hram777 [196]2 years ago
5 0

Answer:

A

Step-by-step explanation:

The picture is rotated about it's mean position

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If 4 daps = 7 yaps, and 5 yaps = 3 baps, how many daps equal 42 baps? **GIVING OUT BRAINLIEST**
Montano1993 [528]

Answer:

40 daps

Step-by-step explanation:

lets say daps is d, yaps are y and baps are b

4d = 7y, 5y=3b

First convert to y

4/7d = y

Now convert that to b

5(4d/7) = 3b

20d / 7 = 3b

20d / 21 = b

Plug it in:

42(20d/21)

40d

aka 40 daps

4 0
2 years ago
There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being
Natalija [7]
Well, the keyword here is One of the performers insist on being the last.

So, the amount of performers that we can arrange freely is 7 performers.

Different ways we can schedule their appearance is :

7 ! = 7 x 6  x 5 x 4 x 3 x 2 x 1
   
 
    = 5040

hope this helps
5 0
3 years ago
How can you prove:<br><br> secθ = cscθtanθ
zavuch27 [327]

\sec \theta=\csc \theta\tan \theta\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\sin \theta}\cdot\dfrac{\sin \theta}{\cos \theta}\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\cos \theta}

3 0
2 years ago
Plsss help this is a math problem
Darina [25.2K]
There are 4 terms in the expression
5 0
3 years ago
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Adult entrance fees to amusement parks in the United States are normally distributed with a population standard deviation of 2.5
kondor19780726 [428]

Answer:  1.509

Step-by-step explanation:

The formula of Margin of Error for (n<30):-

E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 22

Level of confidence = 0.99

Significance level : \alpha=1-0.99=0.01

Using the t-distribution table ,

Critical value : t_{n-1, \alpha/2}=t_{21,0.005}= 2.831

Standard deviation: \sigma=\text{ 2.5 dollars }

Then, we have

E=( 2.831)\dfrac{2.5}{\sqrt{22}}\approx1.509

Hence, the margin of error for a 99% confidence interval for the population mean =1.509

4 0
3 years ago
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