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3241004551 [841]
3 years ago
10

How to write 2.51 in expanded form

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0
When you write in expanded form, you take apart the number by value and place value, and rewrite the number as an addition expression.
The answer is 2+0.51.
Hope that helped you.
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Identify if equations are functions or not functions (see photo) sort them out please
Sav [38]

Answer:

B AND B Because they are the only awnsers that make grammatical sense.

6 0
2 years ago
Find the directional derivative of the function at the given point in the direction of the vector v. G(r, s) = tan−1(rs), (1, 3)
alexandr1967 [171]

The <em>directional</em> derivative of f at the given point in the direction indicated is \frac{5}{2}.

<h3>How to calculate the directional derivative of a multivariate function</h3>

The <em>directional</em> derivative is represented by the following formula:

\nabla_{\vec v} f = \nabla f (r_{o}, s_{o})\cdot \vec v   (1)

Where:

  • \nabla f (r_{o}, s_{o}) - Gradient evaluated at the point (r_{o}, s_{o}).
  • \vec v - Directional vector.

The gradient of f is calculated below:

\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{\partial f}{\partial r}(r_{o},s_{o})  \\\frac{\partial f}{\partial s}(r_{o},s_{o}) \end{array}\right]   (2)

Where \frac{\partial f}{\partial r} and \frac{\partial f}{\partial s} are the <em>partial</em> derivatives with respect to r and s, respectively.

If we know that (r_{o}, s_{o}) = (1, 3), then the gradient is:

\nabla f(r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{s}{1+r^{2}\cdot s^{2}} \\\frac{r}{1+r^{2}\cdot s^{2}}\end{array}\right]

\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{1+1^{2}\cdot 3^{2}} \\\frac{1}{1+1^{2}\cdot 3^{2}} \end{array}\right]

\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right]

If we know that \vec v = 5\,\hat{i} + 10\,\hat{j}, then the directional derivative is:

\nabla_{\vec v} f = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right] \cdot \left[\begin{array}{cc}5\\10\end{array}\right]

\nabla _{\vec v} f (r_{o}, s_{o}) = \frac{5}{2}

The <em>directional</em> derivative of f at the given point in the direction indicated is \frac{5}{2}. \blacksquare

To learn more on directional derivative, we kindly invite to check this verified question: brainly.com/question/9964491

3 0
2 years ago
Find the value of y so that the points (-5,10) and (3,y) lie on a line with slope -3/8.
shtirl [24]

Answer:

y = 7

Step-by-step explanation:

calculate the slope m using the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 5, 10) and (x₂, y₂ ) = (3, y)

m = \frac{y-10}{3+5} = \frac{y-10}{8}

For this to equal - \frac{3}{8}

since the denominators are equal, equate the numerators

y - 10 = - 3 ( add 10 to both sides )

y = 7


8 0
3 years ago
What is the differentiation of (sin3x-cos4x)(tan6x+sec8x)
Ksenya-84 [330]

Answer:

expanded:

y = sin(4x)*sin(4x)*cos(3x)

need to use the product rule and chain rule

look at individual derivatives, use chain rule

d/dx sin(4x) = 4cos(4x)

d/dx cos(3x) = -3sin(3x)

put it together using product rule

dy/dx = 4cos(4x)*sin(4x)*cos(3x) + 4cos(4x)*sin(4x)*cos(3x) - 3sin(3x)*sin(4x)*sin(4x)

simplify

dy/dx = 8cos(4x)*sin(4x)*cos(3x) - 3sin(3x)*sin2(4x)

answer is A.

Hope it helps friend request me and I'll accept xx:)

4 0
3 years ago
HELP!! No idea how to do this
Jlenok [28]

Answer:

D

Step-by-step explanation:

it's the only one where the y of each point has a linear (even if constant) trend, the others go up and down

4 0
3 years ago
Read 2 more answers
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