Question

Jacobi measured the diagonals of three tv screens qs 5√84 inches 46 2/3 inches and 46.625 inches which shows the lengths of the diagonals in n ascending order?

Answer 1

Answer:

The TV with the shortest diagonal is first TV with  45.845 ", followed by the third TV with 46.625" and the longest is the second TV with 46.666 "

Step-by-step explanation:

what we must do is pass calculate the value in each case, like this:

first tv, 5√84

We do the multiplication, first calculating the square root of 84.

5√84 = 45.825

that is, the diagonal of the first TV is 45.845 inches

second tv, 46 2/3

in this case it is a mixed number with integer and fractional part, the integer part is 46 and 2/3 is the fractional part, which is 0.666

Thus:

46 2/3 = 46.666

that is, the diagonal is 46.666 inches

On the third TV, it is directly 46.625

In other words, the TV with the shortest diagonal is 45.845 ", followed by the third TV with 46.625" and the longest is 46.666 "