Answer:
(5,6)
Step-by-step explanation:
8X +6Y=4
Y=-3X+9
Substitute the second equation into the first. Every place you see y put -3x+9)
8x +6(-3x+9)=4
Distribute
8x-18x +54 = 4
Combine like terms
-10x +54 = 5
Subtract 54 from each side
-10x +54-54=4-54
-10x = -50
Divide by -10
-10x/-10 = -50/-10
x= 5
Now we need to find y
y = -3x+9
y = -3(5) +9
y = -15+9
y= 6
(5,6)
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that 
. Then, the normal probability density function for the random variable X is given by
![f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%285%29%5E%7B2%7D%7D%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%285%29%5E%7B2%7D%7D%5D)
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
9514 1404 393
Answer:
- Tyler
- 2 hundredths of a mile
Step-by-step explanation:
The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.
At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.
Then in 10 minutes, Tyler will run ...
distance = speed · time = 1 mile/(8 1/3 min) · 10 min
= 1/(25/3)·10 = 10·3/25 = 30/25 = 1.2 . . . . miles
__
The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...
10 = 8.5x
x = 10/8.5 ≈ 1.18 . . . . miles
So, Tyler runs farther in 10 minutes by a distance of ...
1.20 -1.18 = 0.02 . . . . miles
He ran 14 km, multiply 6 by 2 and 1/3.
