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IRISSAK [1]
3 years ago
9

Suppose the function f(x) = 2x + 12

Mathematics
1 answer:
yarga [219]3 years ago
5 0
First figure out how much it costs to rent seven movies a month. f(7)=2(7) + 12–> 14 + 12–> $26 Now we need to find the difference between 26 and 10. 26 - 10= 16. So Casey needs $16 more to rent 7 movies a month
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I need help please thanks!
Natasha_Volkova [10]

Answer:

f=39

Step-by-step explanation:

hi! first, we can multiply by 12 on both sides to eliminate the 12 in the denominator.

f+3= (7/2)*12

f+3=84/2

f+3=42

now, subtract 3 on both sides.

f=39

7 0
3 years ago
Mr. Cobb is carpeting a 17.7 m long hallway. He has a piece of carpet 22 m long. How much does Mr. Cobb need to cut off the leng
Y_Kistochka [10]

Answer:5.7

Step-by-step explanation:

5 0
3 years ago
In the equation y=-x 4 what is the unit rate?
ioda
The unit rate is -1. because the unit rate has to have a denominator of 1.
4 0
3 years ago
A market research company conducted a survey to find the level of affluence in a city. They defined the category "affluence" for
malfutka [58]

Answer:

A 95% confidence interval for this population proportion is [0.081, 0.159].

Step-by-step explanation:

We are given that a market research company conducted a survey to find the level of affluence in a city.

Out of 267 persons who replied to their survey, 32 are considered affluent.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                            P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of people who are considered affluent = \frac{32}{267} = 0.12

            n = sample of persons = 267

            p = population proportion

<em>Here for constructing a 95% confidence interval we have used One-sample z-test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                    of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

    = [ 0.12-1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } } , 0.12+1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } } ]

    = [0.081, 0.159]

Therefore, a 95% confidence interval for this population proportion is [0.081, 0.159].

4 0
3 years ago
What is the value of the expression 2x2 + 3x-y – 4y2 when x = 2 and y = –4?
sdas [7]
Write the problem: 2x^2+3x-y-4y^2
Substitute x and y: 2(2)^2+3(2)-(-4)-4(-4)^2
Exponents and Multiplication: 8+6+4-64
Add and Subtract: -46

Your Answer is -46
7 0
3 years ago
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