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3 years ago

Solve these please, thanks in advance!

Mathematics

1 answer:

Llana [10]3 years ago

7 0

C) -64
d)-64
E)64
g)-1
h)1

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the scale of a model railroad set is 3.5 millimeters to one foot if the length of a model car in the set is 150 millimeters what

Montano1993 [528]

$\bf \begin{array}{ccll} \stackrel{mm}{model}&\stackrel{ft}{actual}\\ \cline{1-2} 3.5&1\\ 150&x \end{array}\implies \cfrac{3.5}{150}=\cfrac{1}{x}\implies x=\cfrac{150\cdot 1}{3.5}\implies x\approx 42.86$

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3 years ago

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What is the probability that it will be blue?

anastassius [24]

Since its out of 15 marbles all together and all you need to find is the probability of 3 blue marbles you would have to divide 3 by 15. The outcome would be 0.2 or in your case... B. - 0.20

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3 years ago

-3(x + 5) + 8 = 2(x + 4) - 6

Elodia [21]

-3x+(-15)+8=2x+8-6
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3 years ago

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Jackson Middle School has 3 students in choir for every 1 student in band. If there are 52 students in band, how many students a

Monica [59]

Answer:

A. 156 students are in choir

Step-by-step explanation:

It states that for every 3 students in choir equals 1 student in band which give you the equation 1x3. So if band has 52 students then your new equation is 52x3 which is 156! Hope this helps!:)

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3 years ago

In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha

lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement, Reason

1. $\overline{DE} \parallel \overline{AC}$ , Given

2. $\overline {AB}$ is a transversal , Conclusion from statement 1.

We note that ∠BDE and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC, Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B, Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B + ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE, Angle Angle Similarity Postulate

6. BD/BA = BE/BC, Converse of the Side-Side-Side Similarity Theorem

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3 years ago