3 years ago

If possible, factor 169x^2 − y^2.

Mathematics

1 answer:

Mama L [17]3 years ago

7 0

Answer:

(13x - y)(13x + y)

Step-by-step explanation:

Both 169x^2 and y^2 are perfect squares.

The (special) rule for factoring the difference of two squares is

a^2 - b^2 = (a - b)(a + b).

Therefore, 169x^2 and y^2 = (13x - y)(13x + y)

You might be interested in

Can someone help me understand this.

3241004551 [841]

Answer:

easy-peasy

Step-by-step explanation:

Perimeter:

P=2(a+b)

P=2(50+70)

P=2(120

P=240

Area:

A=50*70

A=3,500

I really hope it helped:)

8 0

3 years ago

Read 2 more answers

What is the minimum product of two numbers whose difference is 36? What are the numbers?

GalinKa [24]

Is suppose 36 and 0 would be the best.
36 - 0 = 36
36 x 0 = 0
Seems like that’s the answer

7 0

3 years ago

What is sin θ when sec θ = square root of 5? Rationalize the denominator if necessary.

alexandr1967 [171]

$\bf sec(\theta )=\sqrt{5}\implies \cfrac{1}{cos(\theta )}=\sqrt{5}\implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{5}}}=cos(\theta )~\hfill \leftarrow \stackrel{\textit{let's find the}}{\textit{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}$

$\bf \pm\sqrt{(\sqrt{5})^2-1^2}=b\implies \pm\sqrt{5-1}=b\implies \pm\sqrt{4}=b\implies \pm 2=b \\\\[-0.35em] ~\dotfill\\\\ sin(\theta )=\pm\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{\sqrt{5}}}\implies \stackrel{\textit{rationalizing the denominator}}{\pm\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \pm\cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \pm\cfrac{2\sqrt{5}}{5}}$