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vivado [14]
3 years ago
10

If possible, factor 169x^2 − y^2.

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

(13x - y)(13x + y)

Step-by-step explanation:

Both 169x^2 and y^2 are perfect squares.

The (special) rule for factoring the difference of two squares is

a^2 - b^2 = (a - b)(a + b).

Therefore,      169x^2 and y^2 = (13x - y)(13x + y)

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What is the least common multiple of 24 and 9 *<br> 3<br> 1<br> 72<br> 216
notka56 [123]

Answer:

<h3>The least common multiple of 24 and 9 is 72.</h3>

Step-by-step explanation:

<h3>I hope l helped you ❤❤</h3>
7 0
3 years ago
Line p passes through A(-2, -4) and has a slope of - 1/2
Alenkasestr [34]
M = -1/2
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Find the equation
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3 years ago
Solve For X<br> (see picture below) <br><br> thank you!
Mashutka [201]

Answer:

x = 12

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, then

The square of the tangent is equal to the product of the external part and the entire secant, that is

x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )

x = \sqrt{144} = 12

8 0
3 years ago
having trouble with this problem, pls help :/ I know the answer, just not how to get there. (ap calc ab, integrals)
pochemuha

Answer: D) 101

Step-by-step explanation:

By linearity, we can break it up into 2 integrals. The integral and derivative of f easily cancel out

\int\limits^{10}_{-1} {(2x+0.5f'(x))} \, dx =\int\limits^{10}_{-1} {2x} \, dx +0.5\int\limits^{10}_{-1} {f'(x)} \, dx =x^2|^{^{10}}_{_{-1}}+0.5f(x)|^{^{10}}_{_{-1}}\\=(100-1)+0.5(f(10)-f(-1))=99+0.5(8-4))=101

I used the table for values of f(x) at 10 and -1. Wouldn't be surprised if this was part of a series of questions about f because I really can't see how you could use the hypothesis that f is twice differentiable on R. Same for the other table values. I'm curious about how you found the answer. Was it a different way?

7 0
3 years ago
Solve for x<br> x^9=12^2x12^7
jekas [21]

Answer:

<h2>12</h2>

Step-by-step explanation:

Hi!

Here is your answer,

I will explain in step by step,

{x}^{9}  =  {12}^{2}  \times  {12}^{7}

Here we can simplify this further using this law,

{a}^{m}  \times {a}^{n} =  {a}^{m + n}

So we will get,

{x}^{9}  =  {12}^{7  + 2}  \\  {x}^{9} =  {12}^{9}

Since the powers are same we can cancel it out and we will get,

x = 12

(Hope this answer helped :))

4 0
3 years ago
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