Question

Let f(x) = 8x3 − 22x2 − 4 and g(x) = 4x − 3. Find f of x over g of x

Answer 1

Answer:

$\frac{f(x)}{g(x)}=\frac{2(4x^3-11x^2-2)}{4x-3}$

Step-by-step explanation:

The given functions are.....

$f(x)= 8x^3-22x^2-4\\ \\ g(x)=4x-3$

Using the above functions, we will get......

$\frac{f(x)}{g(x)}\\ \\ =\frac{8x^3-22x^2-4}{4x-3}\\ \\ =\frac{2(\frac{8x^3}{2}-\frac{22x^2}{2}-\frac{4}{2})}{4x-3}\\ \\ =\frac{2(4x^3-11x^2-2)}{4x-3}$

Answer 2

F(x) = 8x³ - 22x² - 4
g(x) = 4x - 3

$(f \div g)(x) = \frac{8x^{3} - 22x^{2} - 4}{4x - 3}$
$(f \div g)(x) = \frac{2(4x^{3}) - 2(11x^{2}) - 2(2)}{4x - 3}$
$(f \div g)(x) = \frac{2(4x^{3} - 11x^{2} - 2)}{4x - 3}$