The fraction of the variability in fuel economy is accounted for by the engine size is 59.91%.
Given that, r= -0.774.
To solve such problems we must know about the fraction of the variability in data values or R-squared.
<h3>What fraction of the variability in fuel economy is accounted for by the engine size?</h3>
The fraction by which the variance of the dependent variable is greater than the variance of the errors is known as R-squared.
It is called so because it is the square of the correlation between the dependent and independent variables, which is commonly denoted by “r” in a simple regression model.
Fraction of the variability in data values = (coefficient of correlation)²= r²
Now, the variability in fuel economy = r²= (-0.774)²
= 0.599076%= 59.91%
Hence, the fraction of the variability in fuel economy accounted for by the engine size is 59.91%.
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See the picture to better understand the problem
F________G_______H_______I
we know that
FI=FG+GH+HI-----> solve for GH
GH=FI-FG-HI
FI=7 units
FG=2 units
HI=1 unit
substitute
GH=7-2-1-----> GH=4 units
the answer is
GH=4 units
Answer:
<h2>9 in</h2>
Step-by-step explanation:
Since the square canvas was completely covered using 77.8 in.² of fabric without any overlap, to get the side length of the canvas, we will use the formula for calculating the area of a square.
Area of a square = Length * Length
A = L*L
A = L²
Given the Area of the area of the square canvas as 77.8 in², on substituting this values into the formula to get L we have;
77.8 = L²
Take the square root of both sides
√77.8 = √L²
L = √77.8
L = 8.82 in
L ≈ 9inches
The length 8.82in gotten was approximated to 9in because <em>the first value after the decimal point is greater that 4 and once we have such case 1 will be added to the value before the decimal point i.e 8 to make it 9</em>.
<em>Hence measurement that is closest to the side length of this canvas in inches is 9inches.</em>
<em></em>
The solution of the quadratic equation is x = 0 or x = 6 ⇒ 4th answer
Step-by-step explanation:
The form of the quadratic equation is ax² + bx + c = 0, where
- a is the coefficient of x²
- b is the coefficient of x
- c is the numerical term
The quadratic equations has two roots, to find them factorize it into two factors and equate each factor by zero
∵ 3x = 0.5 x²
- Subtract 3x from both sides
∴ 0 = 0.5x² - 3x
- Multiply both sides by 2 to make the coefficient of x² integer
∴ 0 = x² - 6x
- Switch the two sides
∴ x² - 6x = 0
- Factorize it by taking x as a common factor
∴ x(x - 6) = 0
- Equate each factor by 0
∴ x = 0 → 1st root
∴ x - 6 = 0
- Add 6 to both sides
∴ x = 6 → 2nd root
∴ The roots of the equation are 0 or 6
The solution of the quadratic equation is x = 0 or x = 6
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