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3 years ago

10

The resultant force, R, is related to two concurrent forces, X and Y, acting at right angles to one another, by the formula R2=X

2+Y2. Rewrite the formula for Y.

1 answer:

riadik2000 [5.3K]3 years ago

6 0

R^2 = X^2 + Y^2
Y^2 = R^2 - X^2
Y = sqrt(R^2 - X^2)

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Which box-and-whisker plot represents the data?

algol [13]

Step 1: arrange the data points in order
12 14 24 30 35 40 42 50 53 Step 2 : Find the median.
median is 35. Step 3. divide the data points into two : left and right
of median

12 14 24 30 and 40 42 50 53
Step 4: find median of each12 14 24 30 : (14+24)/2 = 1940 42 50 53 : (42+50)/2 = 46
step 5. draw lines on the scale on the median, two other
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Answer is B.

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4 years ago

A square fits exactly inside a circle with each vertices being on the circumference of the circle. The square has a side length

GarryVolchara [31]

Answer:

Therefore,

The value of x is 5.97 cm.

Step-by-step explanation:

Given:

Let the length of side of Square be "x" cm'.

Radius of Circle be "r"

Area of Circle = 56 cm squared

pi = 3.14

To Find:

x = ?

Solution:

We know Area of Circle is given by,

$\textrm{Area of Circle}=\pi r^{2}$

Substituting the values we get

$56=3.14\times r^{2}\\r^{2}=17.83\\Square\ Rooting\\r=\sqrt{17.83}=4.22\ cm$

We have, a square fits exactly inside a circle with each vertices being on the circumference of the circle,

Vertex Angle of a Square is 90°.

In a Circle Diameter Subtends a Right angle,

So it's Diagonal will be the Diameter,

$Diagonal =Diameter$

$Diameter=2\times Radius$

Substituting the values we get

$Diameter=2\times 4.22=8.44\ cm$

Therefore,

$Diagonal = 8.44\ cm$

Also we know that,

Length of Diagonal of a Square for side "x" is given by,

$Diagonal=\sqrt{2}\times x$

Substituting the values we get

$x=\dfrac{8.44}{\sqrt{2}}=5.967\approx 5.97\ cm$

Therefore,

The value of x is 5.97 cm.

3 0

4 years ago

Encuentra la medida del segmento AB conociendo que : DE//BC medida del ángulo EDA=90 grados ,AD=2cm,DE=3cm y BC=18cm

OverLord2011 [107]

Hii its charli damelio

5 0

3 years ago

the length of a rectangle is 24 units. can the perimeter x of the rectangle be 60 units when its width y is 11 units

S_A_V [24]

24 +24 = 48

11 + 11 = 22

48 +22 = 70

the perimeter cannot be 60 with dimensions of 24 & 11

5 0

4 years ago

Read 2 more answers

In △MDK, m=16.4, d=22, and k=19. Identify m∠D rounded to the nearest degree. The figure shows triangle M D K. The length of side

Alex_Xolod [135]

The length of the sides,MD, DK, and KM gives the measure of the angle m<D as c) 76°

<h3>Which method can be used to find the measure of angle m<D?</h3>

In triangle ∆MDK, we have;

m = 16.4

d = 22

k = 19

Using cosine rule, we get;

d² = m² + k² - 2•m•k•cos(D)

Therefore;

2•m•k•cos(D) = m² + k² - d²

$D = arccos \left( \frac{ {m}^{2} + {k}^{2} - {d}^{2} }{2 \cdot m \cdot k} \right)$

Which gives;

$D = arccos \left( \frac{ {16.4}^{2} + {19}^{2} - {22}^{2} }{2 \times 16.4 \times 19} \right) \approx {76}^{ \circ}$

m<D = 76°

The correct option is therefore;

c) 76°

Learn more about the rule of cosines here:

brainly.com/question/4316134

#SPJ1

6 0

2 years ago