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9966 [12]
3 years ago
13

Translate each equation into a verbal sentence 13 = 2 + 6t

Mathematics
1 answer:
Mama L [17]3 years ago
5 0

thirteen  is equal to two plus six T. Hope this can help. Have a wonderful day. : )

You might be interested in
What is three ways to express 3^5 as a product of powers
schepotkina [342]

Three ways to express it as a product of powers are:

3x3x3x3x3

3^5

243

Hope I helped!

Good Luck!

3 0
3 years ago
Find each percent increase or decrease to the nearest percent:
Svet_ta [14]
From 10 to 15 -> 10 increased with half its size (5), that means increase of 50%
From 16 to 12 -> decrease of 4, which is a quarter of 16, that means a decrease of 25%
4 0
3 years ago
5x + 6y = 18 and 18x -15y =36
stira [4]
5x+6y=18

5x=18-6y

x=(18-6y)/5

Use that in the other equation
18(18-6y)/5 - 15y = 36

64.8-21.6y - 15y = 36

28.8=36.6y
.7868=y

Now put that number in for y on the first equation

5x+6(.78) = 18
5x + 4.68 = 18
5x = 13.32
x = 2.66
and y = .78


4 0
3 years ago
Read 2 more answers
Solve x^2 – 2x – 15 = 0 using the zero product property.
lawyer [7]
You could just factor out the Trinomial and find the zeros of the equation,

x^2 - 2x -15 = (x - 5)(x + 3) = 0,

x - 5 = 0 and x + 3 = 0, so x = 5,-3 AKA answer choice C
8 0
2 years ago
A 24-centimeter by 119-centimeter piece of cardboard is used to make an open-top box by removing a square from each corner of th
satela [25.4K]

Answer:

The size square removed from each corner = 32.15 cm²

Step-by-step explanation:

The volume of the box = Length * Breadth * Height

Let r be the size  removed from each corner

Note that at maximum volume, \frac{dV}{dr} = 0

The original length of the cardboard is 119 cm, if you remove a  size of r (This typically will be the height of the box)  from the corner, since there are two corners corresponding to the length of the box, the length of the box will be:

Length, L = 119 - 2r

Similarly for the breadth, B = 24 - 2r

And the height as stated earlier, H = r

Volume, V = L*B*H

V = (119-2r)(24-2r)r

V = r(2856 - 238r - 48r + 4r²)

V = 4r³ - 286r² + 2856r

At maximum volume dV/dr = 0

dV/dr = 12r² - 572r + 2856

12r² - 572r + 2856 = 0

By solving the quadratic equation above for the value of r:

r = 5.67 or 42

r cannot be 42 because the  size removed from the corner of the cardboard cannot be more than the width of the cardboard.

Note that the area of a square is r²

Therefore, the size square removed from each corner = 5.67² = 32.15 cm²

5 0
3 years ago
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