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Ksenya-84 [330]
2 years ago
5

PLEASE help no scam or ill report

Mathematics
1 answer:
dezoksy [38]2 years ago
5 0

Answer:

These opposite angles are called  Vertical Angles.

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9- 4(2p+3) - 8p+7<br> how do i solve this ?
Sholpan [36]

Answer:

= -16p+4

Step-by-step explanation:

First we simplify:

9-4(2p+3)-8p+7

Then we distribute:

=9+(-4)(2p)+(-4)(3)+(-8p)+7\\=9+(-8p)+(-12)+(-8p)+7

Lastly, combine like terms:

=9+-8p+-12+-8p+7\\=(-8p+-8p)+(9+-12+7)\\=-16p+4

Hope this helps!

Have a good evening! :)

7 0
2 years ago
Select the correct answer. Select the place where the digit 5 sits in this number. 952,832,744 A. hundred millions B. one billio
k0ka [10]

Count the amount of digits from right to left:

The digit 5 appears at the eighth position.

Remember that the 7th position is for millions. So, the eighth position is for ten millions.

Therefore, the place where the digit 5 sits in the number 952,832,744 is ten millions.

4 0
1 year ago
How many times larger is 3*10^8 than 5*10^6
Alex777 [14]
60 times larger.
Hope I helped!!!
8 0
3 years ago
A survey found that 8 out of 10 parents approved of the new principal’s performance. If 4 parents name are chosen with replaceme
Natasha2012 [34]

Answer:

The probability is 0.044

Step-by-step explanation:

Step-by-step explanation:

Let p be the probability that the new principal’s performance is approved.

This is obtainable from the survey and it is 8/10 = 0.8

Let q be the probability that the new principal’s performance is disproved.

That will be;

1 - q = 1- 0.8 = 0.2

To calculate the probability that 14 parents names are chosen at random and they all

approve of the principal’s performance, we use the Bernoulli approximation of the binomial theorem.

That will be;

14C14 * p^14 * q^0

= 1 * 0.8^14 * 0.2^0

= 0.043980465111 which is approximately 0.044

8 0
3 years ago
Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
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