Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
The answer is letter C.Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.
The force of attraction between any two masses is called Newton's Law of Universal Gravitation:


is simply a given constant.
If we're at the surface of Eath,

refers to the mass of the Earth,

to the mass of whatever is on the surface of Earth, and

to the radius of Earth.
Normally, we define a constant

to be equal to

; in which

is the mass of Earth and

the radius of earth;

happens to be around 9.8.
By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

As you can see, weight is directly proportional to mass, more mass implies more weight.
∆S>_closed integral of dQ/T
There are many equations for different situations of entropy but this is a general one
I think is True! Is the best answer. Because the trumpet it make them sounds like the lips with the musician and it vibrate.
The answer would be D. Because the iron fillings are attracted to the magnet underneath the glass.