V=D/T
V is speed
D is distance
T is time
V=D/T
31.67 m/s = 1361.81 m / T
31.67/31.67=1361.81/31.67
T=43 seconds
Hope this helps
X =(3.00x4.00 x3-1.00t x 2.00) x m
x= (12.00x3- 1.00 x2.00) x m
x= 36.00 -1.00 x 2.00) x m
x = (36.00 -2.00) x m
x =( 34.00) x m
x =34.00 times m
Answer:
The angular frequency is the coil rotating is 1.9 rad/s.
Explanation:
Given that,
Number of turns = 600
Radius = 15 cm
Magnetic field = 0.020 T
Maximum induced emf = 1.6 V
We need to calculate the angular frequency is the coil rotating
Using formula emf

When induced emf is maximum so
will be 1.

Where, N = number of turns
A = area
B = magnetic field
Put the value into the formula


Hence, The angular frequency is the coil rotating is 1.9 rad/s.
Answer:
Explanation:
The magnetic moment of the coil M = current x area of loop
= I x L x L
M = L² I .
Magnetic field = B
Torque = M x B
= MB sinθ where θ is angle between M and B . Direction of M is perpendicular to face of loop
Torque = MB sin90
= MB
= L² I B .
75 because 25 plus 75 equals 90