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4 years ago

According to the law of reflection the angle of incidence is equal to the angle of blank

Physics

2 answers:

mariarad [96]4 years ago

8 0

The answer should be:

Angle Of incidence is equal to angle of reflection.

Eduardwww [97]4 years ago

7 0

Answer:

The word that goes into the blank is reflection.

Explanation:

Angle of incidence is the angle made by the ray with the normal to the surface it hits and angle of reflection is the angle made by ray with the normal to the surface after it gets reflected from the surface.

As per law of reflection,

Angle of incidence = Angle of reflection

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If you went to a planet with an acceleration due to gravity of 20 m/s^2 and twirled a bucket of water, what happens to the angul

wel

Answer:

Explanation:

It's Scientifically proven

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4 years ago

A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu

nikitadnepr [17]

Answer:

$W = 3542.7 J$

Explanation:

As per ideal gas law we know that

PV = nRT

so we have

$P = 1.01 \times 10^5 Pa$

$n = \frac{92}{28} = 3.28 moles$

T = 200 K

now we have

$(1.01 \times 10^5) V = 3.28 (8.31)(200)$

$V_1 = 0.054 m^3$

Now we know that if pressure remains constant

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

$\frac{0.054}{200} = \frac{V_2}{70}$

$V_2 = 0.0189 m^3$

Now work done in this process is given as

$W = P \Delta V$

$W = (1.01 \times 10^5)(0.054 - 0.0189)$

$W = 3542.7 J$

3 0

3 years ago

What is the distance between a(-6,3),b(-2,4),c(-8,3)

Schach [20]

Answer:

Explanation:

Appears to be the vertexes of a triangle.

AB = √(-6 - (-2))² + (3 - 4)²) = √17

AC = √(-6 - (-8))² + (3 - 3)²) = 2

BC = √(-2 - (-8))² + (4 - 3)²) = √37

8 0

3 years ago

Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m

Oksi-84 [34.3K]

Answer:

Observed time, t = 5.58 s

Explanation:

Given that,

Speed of light in a vacuum has the hypothetical value of, c = 18 m/s

Speed of car, v = 14 m/s along a straight road.

A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.

We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :

$T=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}} }$

t is observed time.

$t=T\times \sqrt{1-\dfrac{v^2}{c^2}} \\\\t=8.89\times \sqrt{1-\dfrac{14^2}{18^2}} \\\\t=5.58\ s$

So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.

4 0

3 years ago

A horizontal force of 200 n is applied to move a 55-kg cart (initially at rest) across a 10-m level surface. what is the final k

Vesnalui [34]

<span>Kinetic energy is the energy that is possessed by an object that is moving. It is calculated by one-half the product of the mass and the square of the velocity of the object. We need to determine the velocity of the cart that is moving.
</span>
First, we use Newton's Second Law of motion;
<span>Force = ma
200 = 55a
a = 3.64 m/s^2

Then, from the kinematic equation we calculate the velocity;
v^2 = v0^2 + 2ax

where v is the final velocity, v0 is the initial veocity (zero since it initially start at zero), a is the acceleration ( 3.64 m/s^2) and x is the distance traveled.

v^2 = 0^2 + 2 (3.64) (10)
v^2 = 72.73 m^2 / s^2
v = 8.53 m / s

KE = mv^2 / 2
KE = 1/2 (55) (8.53^2)
KE= 2000 J</span>

7 0

3 years ago