It is responsible for all electrostatic effects and underlies most macroscopic forces. The Coulomb force is extraordinarily strong compared with the gravitational force, another basic force—but unlike gravitational force it can cancel, since it can be either attractive or repulsive.
Answer:
the mass should be bring closer to the point about which we are finding torque
Explanation:
τ = Σr × F = rmg
where m is the mass, g is acceleration due to gravity, and r is the distance
Torque is directly proportional to -
1.mass, m , of object
2. distance, r, of the mass from the point about which we are finding the torque.
So if we increase or decrease them then the torque will also increase or decrease.
So if we increase the mass the torque will increase but since we have to maintain same torque therefore we have to decrease the distance of mass from the point about which we are finding torque.
Therefore the mass should be bring closer to the point about which we are finding torque.
Answer:
1.962 × 10⁻³ kW
Explanation:
The energy of a wave of a wave, such as an ocean wave, in regions of considerable water depth given its amplitude in a meter of crest and surface unit is given by the relation;
Where:
ρ = Density of water = 1000 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
A = Wave amplitude = 2 cm = 0.02 m
We therefore have;
The energy is power is the energy per second which is gives;
P = E /second = 1.962 J/s = 1.962 W = 1.962 × 10⁻³ kW.
Answer:
B
Explanation:
Basta B isagot Mona Tama yan
Answer:
The second ball lands 1.5 s after the first ball.
Explanation:
Given;
initial velocity of the ball, u = 12 m/s
height of fall, h = 35 m
initial velocity of the second, v = 12 m/s
Time taken for the first ball to land;
determine the maximum height reached by the second ball;
v² = u² -2gh
at maximum height, the final velocity, v = 0
0 = 12² - (2 x 9.8)h
19.6h = 144
h = 144 / 19.6
h = 7.35 m
time to reach this height;
Total height above the ground to be traveled by the second ball is given as;
= 7.35 m + 35m
= 42.35 m
Time taken for the second ball to fall from this height;
total time spent in air by the second ball;
T = t₁ + t₂
T = 1.23 s + 2.94 s
T = 4.17 s
Time taken for the second ball to land after the first ball is given by;
t = 4.17 s - 2.67 s
T = 1.5 s
Therefore, the second ball lands 1.5 s after the first ball.