Explanation:
The acceleration on an object due to the gravity of any massive body is represented by g (small g). The force of attraction between any two unit masses separated by unit distance is called universal gravitational constant denoted by G(capital g). The relation between G and g is not proportional. That means they are independent entities.
G and g
In physics, G and g can be related mathematically as –
\(g=\frac{GM}{R^{2}}\)
Where,
1=g is the acceleration due to the gravity of any massive body measured in m/s2.
2=G is the universal gravitational constant measured in Nm2/kg2.
3=R is the radius of the massive body measured in km.
4=M is the mass of the massive body measured in Kg.
Answer:
Work occurs when a force acts on an object and causes a displacement of that object.
Explanation:
a . Force applying over a distance or in other words force causing the movement (displacement) of an object is known as Work.
b. An activity with mental or physical effort is done in order to achieve a result is called work.
c. A constant force integrates the product of the force and distance.
Ex : 1) when the body moves in the direction of force
2) shooting a bullet
3) Pushing a car horizontally from rest
4)walking up stairs
5) sawing a log.
We calculate as follows:
d = 0.025 m
<span>Δx = 0.31 m
</span>
<span>W = pΔV = p(πd²)(Δx/4) </span>
<span>W = 2.4x10⁵(3.14x0.025²)(0.31/4) =36.5 J
</span>
<span>F = W / Δx = 36.5 / 0.31 = 117.8 N
</span>
Hope this answers the question. Have a nice day.
Answer:
P=1.53 i +1.92 j kg.m/s
P=2.45 kg.m/s
α = 51.34
Explanation:
Given that
m=123 g = 0.123 Kg
U= 25 m/s
θ=30°
t= 0.6 s
This is the case of projectile motion
So the horizontal component of velocity U = u cosθ
u = 25 cosθ
u = 25 cos 30°
u=21.65 m/s
The vertical component of velocity U = U sinθ
Vo= U sinθ
Vo= 25 sin 30°
Vo = 12.5 m/s
We know that horizontal component of velocity of ball will remain same.So the horizontal component of momentum
Px= m u
Px= 0.143 x 12.5 kg.m/s
Px=1.53 kg.m/s
The vertical component of ball after 0.6 s
V= Vo- g t
V= 21.65 - 10 x 0.6 m/s
V= 15.65 m/s
Py= m V
Py= 0.123 x 15.65 kg.m/s
Py=1.92 kg.m/s
P=1.53 i +1.92 j kg.m/s
Magnitude P
P=2.45 kg.m/s
Direction
α = 51.34° (measured from x direction)
Answer:
2.5 m/s
Explanation:
There are calculators online that can help you easily calculate the accerlation.