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Darina [25.2K]
1 year ago
10

A car moving with constant acceleration covers the distance between two points 120 m apart in a time of 8.0 s. its speed at the

second point is 12 m/s. what is the speed of the car at the first point?
Physics
1 answer:
Shalnov [3]1 year ago
7 0

The speed of the car at the first point is 18 m/s.

How do we calculate the initial speed?

The equation we can be used for finding the speed of the first point is:

         ⇒ Δx = ½ (v + v₀)t

From this we can easily calculate v₀ i.e,

        ⇒ v₀ = 2Δx/t - v

According to the question it is given that,

Distance between two points is , Δx =120 m,

Time t = 8.0 s,

Speed at second point is, v = 12 m/s,

Speed at first point is, v₀ = ?

From above formula,

 ⇒  v₀ = 2Δx/t - v

           = 2×120/8 - 12

           = 240-96/8

           = 144/8

           = 18 m/s

Therefore the speed at first point is 18 m/s.

To know more about the calculation of speed, visit the given link:

brainly.com/question/19905871

#SPJ4

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