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Iteru [2.4K]
4 years ago
13

Will kilogram of hydrogen contains more atoms than kilogram of lead?

Physics
1 answer:
Zigmanuir [339]4 years ago
4 0
Yes a kg of hydrogen will have more atoms than a kg of lead, because lead has a higher atomic mass, than hydrogen so it will take more atoms of hydrogen to make a kg than lead
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Forces always come in pairs — so each ______ has a reaction
Wittaler [7]
Every action has an equal opposite reaction
7 0
3 years ago
You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of
solong [7]

Answer:

The velocity of the man from the frame of  reference of a stationary observer is, V₂ = 5 m/s

Explanation:

Given,

Your velocity, V₁ = 2 m/

The velocity of the person, V₂ =?

The velocity of the person relative to you, V₂₁ = 3 m/s

According to the relative velocity of two

                                V₂₁ = V₂ -V₁

∴                               V₂ =  V₂₁ + V₁

On substitution

                                 V₂ = 3 + 2

                                      = 5 m/s

Hence, the velocity of the man from the frame of reference of a stationary observe is, V₂ = 5 m/s

8 0
3 years ago
The development of new technology requires the evaluation of the overall benefit to cost ratio of the new technology.
Valentin [98]
D) Ride comfort, i<span>t won't let me answer unless there are 20 characters so I added this pointless sentence.</span>


4 0
4 years ago
Read 2 more answers
If I exert a 203 N force on a 58 kg box, what will the acceleration of the box be?
Anit [1.1K]

Answer:

<h2>3.5 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

m is the mass

f is the force

From the question we have

a =  \frac{203}{58} =  \frac{7}{2}   \\

We have the final answer as

<h3>3.5 m/s²</h3>

Hope this helps you

7 0
3 years ago
A level curve on a country road has a radius of 150 m. What is the maximum speed at which this curve can be safely negotiated on
SSSSS [86.1K]

The maximum speed of the car is 24.3 m/s

Explanation:

For a car moving along an unbanked turn, the frictional force provides the centripetal force required to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force while the term on the right is the centripetal force, and where

\mu=0.40 is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r = 150 m is the radius of the curve

Solving for v, we find the (maximum) speed at which the car can move along the turn:

v=\sqrt{\mu gr}=\sqrt{(0.40)(9.8)(150)}=24.3 m/s

For speed larger than this value, the frictional force is no longer enough to keep the car along the turn.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

8 0
3 years ago
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