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UkoKoshka [18]
3 years ago
14

NoelaniNadia hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Chemistry
1 answer:
kvasek [131]3 years ago
5 0

Answer:

okay then

Explanation:

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Why sodium chloride is a neutral compound even though it is made up of ions that have positive and negative charges?
Black_prince [1.1K]
This is key: remember it's only an ion when it transfers electrons! If it isn't going through the process of the transfer of electrons it's a neutral atom. 
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The primitive atmosphere of Earth may have favored the abiotic synthesis of organic molecules because it __________.
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Answer and Explanation:

The primitive atmosphere of Earth may have favored the abiotic synthesis of organic molecules because it **had close to no oxygen, hence, it was powerfully reducing. It had pure energy sources too in form of ultraviolet rays from the sun (it was extremely hot! Too hot for water in liquid form to exist in fact!), outgassing from the numerous volcanoes and lightning**.

Abiotic synthesis means a formation reaction where the reactants are charged to become products, almost all on their own, with no catalyst especially.

So, these factors would have helped the organic molecules to form as most of what is needed to overcome the energy barrier and become products.

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4 years ago
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Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2
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3 years ago
2Cu + O2 + 315kj - 2CuO. Is what kind of chemical reaction?
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3 0
4 years ago
Calculate the mass of vanadium(V) oxide (V2O5) that contains a million (1.0 *10^6) vanadium atoms. Be sure your answer has a uni
sweet [91]

Answer : The mass of vanadium(V) oxide will be 1.51\times 10^{-16}g

Explanation : Given,

Number of atoms of V_2O_5 = 1.0\times 10^{6}

Molar mass of V_2O_5 = 181.88 g/mole

In V_2O_5, there are 2 atoms of vanadium and 5 atoms of oxygen.

First we have to determine the moles of V_2O_5.

As, 2\times 6.022\times 10^{23} number of vanadium atom present in 1 moles of V_2O_5

So, 1.0\times 10^{6} number of vanadium atom present in \frac{1.0\times 10^{6}}{2\times 6.022\times 10^{23}}=8.3\times 10^{-19} moles of V_2O_5

Now we have to determine the mass of V_2O_5.

\text{Mass of }V_2O_5=\text{Moles of }V_2O_5\times \text{Molar mass of }V_2O_5

\text{Mass of }V_2O_5=(8.3\times 10^{-19}mole)\times (181.88g/mole)=1.51\times 10^{-16}g

Therefore, the mass of vanadium(V) oxide will be 1.51\times 10^{-16}g

4 0
4 years ago
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