Not a lot of rain so it’s dry
If a new beetle was found you would know if it was a invasive species depending on where you found it. A invasive species may be found on a eaten plant or a eaten tree. Although you would have to find a few to be sure.
Answer:
Diamond-
Physical identification characters:
Color- White or Colorless
Lusture - admantine
Streak - Colorkess
Habit - Hour glass structure
Hardness - 10
Cleavage- octaheadral
Composition- pure carbon
Specific gravity-3.5
Dolomite (CaMg(CO3)2
Color - Colorless or white
Hardness is between 3-4
Reacts with any acid
Gneiss
Light and dark strip or banding present alternatively
biotite , pyroxene have Mafic mineral shows dark banding
Quartz, Feldspar have Felsic mineral for light banding
High grade metmorphic rock which is formed due to regional metamorphism of lower grade rock
Chalk(CaCO3)
Color-White
Very fragile
Hardness-1
With acid gives effervescence.
<span>It says: </span>Prokaryotic cells<span> have a simpler structure than eukaryotic </span>cells.<span> Evidence shows that eukaryotic </span>cells<span> evolved from </span>prokaryotic cells.<span> ... </span>Prokaryotes<span> have metabolic functions that eukaryotic </span>cells<span> lack.</span>
The answer is 0.43
To calculate p we will use one of two formulas of the <span>Hardy-Weinberg principle:
</span>
p² + 2pq + q² = 1 and <u>p
+ q = 1</u>
where:
p - the frequency of the allele for long legs which is a dominant trait.
q - the frequency of the allele for short legs which is a recessive trait.
p² - the frequency of dominant homozygote (with long legs)
2pq - the frequency of heterozygote (with long legs)
q² - the frequency of recessive homozygote (with short legs)
So, 33 of 100 organisms have short legs. The frequency of recessive homozygote is represented by q²:
<span>q² = 33/100 = 0.33</span>
⇒ q = √0.33 = 0.57<span>
</span>
Using the formula:
p + q = 1
p = 1 - q = 1 - 0.57 = 0.43
Therefore, p = 0.43