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oksian1 [2.3K]
3 years ago
13

Suppose DK is an angle bisector of △DEF. Given: EK=2, FK=5, DF=10. Find DE.

Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

  DE = 4

Step-by-step explanation:

The bisector divides the triangle into proportional segments, so ...

  FK/DF = EK/DE

  5/10 = 2/DE . . . . substitute given values

  DE = 4 . . . . . multiply by 2DE

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