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masya89 [10]
3 years ago
7

Jack Lawler, a financial analyst, wants to prepare an article on the Shadow Stock portfolio developed by the American Associatio

n of Individual Investors (AAII). A list of the 30 companies in the Shadow Stock portfolio as of March is contained in the Excel Online file below. Use the spreadsheet to answer the following questions.
Jack would like to select a simple random sample of 5 of these companies for an interview concerning management practices.

a. The Shadow Stock companies are listed in column A of the Excel worksheet provided above. In column B we have generated a random number for each of the companies. Use these random numbers to select a simple random sample of 5 of these companies for Jack by finding the smallest random number, the second smallest random number, etc. in column B using an Excel function.

The random numbers corresponding to the first 5 companies selected are (to 5 decimal places):

First company (smallest random number) ____

Second company (2nd smallest random number) ____

Third company (3rd smallest random number) _____

Fourth company (4th smallest random number) _____

Fifth company (5th smallest random number)______

0.15106
0.78664
0.46736
0.31288
0.05743
0.96845
0.70824
0.43701
0.68709
0.49262
0.69531
0.04123
0.51061
0.23796
0.92181
0.91875
0.97469
0.78824
0.30299
0.61512
0.83291
0.05894
0.76809
0.85076
0.61597
0.42998
0.92434
0.36411
0.72285
0.29854
Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
Last one of the first one try the last one first
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Ella and Iris are planning trips to nine countries this year. There are 12 countries they would like to visit. They are deciding
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Using the combination formula, it is found that there are 220 ways to decide which countries to skip.

The order in which the countries are skipped is not important, hence the <em>combination formula </em>is used to solve this question.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem, 3 countries are skipped from a set of 12, hence the number of ways is given by:

C_{12,3} = \frac{12!}{3!9!} = 220

More can be learned about the combination formula at brainly.com/question/25821700

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HELP ASAP GIVING BRAINLIEST
Alborosie
Hey sorry if I’m wrong but I think it is the 665 sorry if I’m wrong let me know
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Suppose that 80 percent of all statisticians are shy, whereas only 15 percent of all economists are shy. Suppose also that 90 pe
Anna71 [15]

Answer:

37.21% probability that the person is a statistician.

Step-by-step explanation:

We have these following probabilities:

An 80% probability that a statistican is shy.

A 15% probability that an economist is shy.

At the gathering, a 90% probability that a person is an economist.

At the gathering, a 10% probability that a person is a statistican.

If you meet a shy person at random at the gathering. What is the probability that the person is a statistician?

This can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the person is a statistican, given that he is shy?

P(B) is the probability of the person being a statistican. So P(B) = 0.1.

P(A/B) is the probability of a statistican being shy, so P(A/B) = 0.8.

P(A) is the probability of a person being a shy. This is 15% of 90%(economists) and 80% of 10%(statisticans). So

P(A) = 0.15*0.9 + 0.8*0.1 = 0.215

Finally

P = \frac{P(B).P(A/B)}{P(A)}

P = \frac{0.1*0.8}{0.215} = 0.3721

37.21% probability that the person is a statistician.

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In the figure, m and n are rays.
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Is there a picture to go along with this??
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