Writing an equation is the easiest way to figure this out.
b = boys, g = girlsb = 3/4g35 students = g + b35 = g + 3/4g35 = 7/4g35/7/4 = g20 girls35 - 20 = b or 3/4(35) = b15 boys
Answer:
d is the answer
Step-by-step explanation:
just read the statements properly
Answer:
The area of the rectangle is 1222 units²
Step-by-step explanation:
The formula of the perimeter of a rectangle is P = 2(L + W), where L is its length and W is its width
The formula of the area of a rectangle is A = L × W
∵ The length of a rectangle is 5 less than twice the width
- Assume that the width of the rectangle is x units and multiply
x by 2 and subtract 5 from the product to find its length
∴ W = x
∴ L = 2x - 5
- Use the formula of the perimeter above to find its perimeter
∵ P = 2(2x - 5 + x)
∴ P = 2(3x - 5)
- Multiply the bracket by 2
∴ P = 6x - 10
∵ The perimeter of the rectangle is 146 units
∴ P = 146
- Equate the two expression of P
∴ 6x - 10 = 146
- Add 10 to both sides
∴ 6x = 156
- Divide both sides by 6
∴ x = 26
Substitute the value of x in W and L expressions
∴ W = 26 units
∴ L = 2(26) - 5 = 52 - 5
∴ L = 47 units
Now use the formula of the area to find the area of the rectangle
∵ A = 47 × 26
∴ A = 1222 units²
∴ The area of the rectangle is 1222 units²
I would say read it well and then write down an equation or expression to represent the data so its easier for you to understand and/or solve.
Answer:
B. Solve each equation for a variable
Is (-1,13) a solution of the system: Yes it is x =1, y= 13
Step-by-step explanation:
-4x=30-2y
- 15 = - 2y + 11x
-4x=30-2y
-2y+4y = -30-------------------i
- 2y + 11x= - 15 ---------------ii
make x the subject of formula in equ i
-4x=30-2y
x= (30-2y)/-4
insert x= (30-2y)/-4 in equ ii
- 2y + 11x= - 15
-2y+ 11((30-2y)/-4)= -15
-2y+(330-22y)/4 = -15
-8y+330-22y/4 = -15
-8y-22y+330/4= -15
cross multiply
-30y+330 = 4x-15 = -60
-30y = -60-330
-30y =--390
y= -390/-30 = 13
if y = 13
x = (30-2y)/-4 = (30-2x13)/-4 = (30-26)/4 = 4/4 = 1
x=1 , y=13
