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Pepsi [2]
3 years ago
14

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 250 people entered the park, a

nd the admission fees collected totaled $750.00. How many children and how many adults were admitted?
Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:

100 children

150 adults

Step-by-step explanation:

c- children

a- adults

---------------

we get equations as per question:

  • 1.5c+4a= 750
  • c+a= 250 ⇒ a= 250- c

  • 1.5c +4(250-c)= 750 ⇒
  • 1.5c- 4c+1000=750 ⇒
  • 2.5 c= 250 ⇒
  • c= 100
  • a= 250-100 ⇒
  • a= 150

Children 100, adults 150

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3 years ago
Please help me out............................
Alina [70]

Answer:

<h2>b = 15°</h2>

Step-by-step explanation:

If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.

We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:

m∠QPR + m∠PRQ + m∠RQP = 180°

We have

m∠QPR = m∠PRQ and m∠RQP = 60°

Therefore

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2(m∠QPR) = 120°           <em>divide both sides by 2</em>

m∠QPR = 60° and m∠PRQ = 60°

Therefore ΔPRQ is equaliteral.

ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore

m∠SPR = m∠PRS

In ΔAPS we have:

m∠SPR + m∠PRS + m∠RSP = 180°

2(m∠SPR) + 90° = 180°            <em>subtract 90° from both sides</em>

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(B)if we take 100 students from the list of math instructor, that will ensure that we have taken students that are taking math class now, and math is part of their study plan, seems fine.

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