Question

Juan has c cheesecakes. Clarence has 5 less than 3 times as many cheesecakes as Juan has and Darlene has 2 more than half as many cheesecakes as Clarence has. Find an expression in terms of $c$ for the total number of cheesecakes Juan, Clarence, and Darlene have.

Answer 1

C= Clarence, J= Juan, and D= Darlene
C= 3J-5
D= C/2+2
J= c

Answer 2

Answer: $c+(3c-5)+\dfrac{1}{2}(3c-5)+2$

Step-by-step explanation:

Given : Juan has c cheesecakes.

Clarence has 5 less than 3 times as many cheesecakes as Juan has .

i.e. Expression for cheesecakes Clarence has = $3c-5$

Darlene has 2 more than half as many cheesecakes as Clarence has.

i.e. Expression for cheesecakes Darlene has = $\dfrac{1}{2}(3c-5)+2$

Now, the  expression in terms of "c" for the total number of cheesecakes Juan, Clarence, and Darlene have:-

$c+(3c-5)+\dfrac{1}{2}(3c-5)+2$