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Vinvika [58]
3 years ago
12

Find two numbers that multiply to 60 and add to 19

Mathematics
1 answer:
victus00 [196]3 years ago
4 0

the answers are 15 times 4.

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Find the length of the radius of the following circle. x² + y² = 16 4 8 16
Morgarella [4.7K]
Please, when you present a list of numbers, such as 4, 8, 16, ..., separate them with commas or semicolons:  4, 8, 16, ...

If x^2 + y^2 = 16, then 16 represents r^2, and r = 4.  r cannot be negative in this type of problem.

5 0
3 years ago
Read 2 more answers
A​ quality-control inspector examined 100 light bulbs and found 7 defective. At this​ rate, how many defective bulbs would there
anastassius [24]

Answer: 175 defective bulbs.

Step-by-step explanation:

1. Keeping on mind that the inspector examined 100 light bulbs and found 7 defective, you can calculate the number of defective bulbs that there would be in a lot of 2500 ​bulbs as following:

- Let's call the number of defective bulbs that there would be in a lot of 2500 ​bulbs x.

- Then, you have:

\frac{100}{7}=\frac{2500}{x}

- Solve for x:

 x=\frac{2500*7}{100}

x=175

2. Then, there would be 175 defective bulbs  in a lot of 2500 ​bulbs.


4 0
3 years ago
At a college, 4/5 of the students take an English class. Of these students, 5/6 Composition. Which fraction of the students at t
Alchen [17]
If I’m doing it correctly it’s 2/3 but I haven’t done it in a while
3 0
3 years ago
The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal
adell [148]

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

a) For x < 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

8 0
3 years ago
Which best explains whether point G can be the centroid?
wariber [46]
The answer is C.
Point G can be centroid because 12:6 equals 2:1

FG = 6
FC = 18
so
GC = 12

12:6 = 2:1
6 0
3 years ago
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