Answer:
The loss would be 1062.50
Step-by-step explanation:
To find this, first convert the purchase price into a decimal.
133/4 = 33.25
Now multiply that my the number of shares bought.
33.25 * 50 = 1662.50
This is the amount that was spent. Now to find the sale price, multiply the number of shares by the new price.
50 * 12 = 600
And to find the total loss, subtract the amount of the purchase price from the sale price.
600 - 1662.50 = -1062.50
Answer:
105ft^2
Step-by-step explanation:
1/2(21+14)*6
1/2(35)*6
17.5*6
105
<h3>Exact area = 12pi - 9*sqrt(3) square inches</h3><h3>Approximate area = 22.1106545749577 square inches</h3>
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Work Shown:
Assuming the chord is horizontal along with the diameter, then this means the two smallest minor arcs are both 30 degrees each. This leaves the northern most arc to be 180-30-30 = 120 degrees in measure
A = area of northern sector (you can think of it as a pizza slize)
A = (angle/360)*pi*r^2
A = (120/360)*pi*6^2
A = 12pi
B = area of triangle
B = (1/2)*side1*side2*sin(included angle)
B = (1/2)*6*6*sin(120)
B = 18*sqrt(3)/2
B = 9*sqrt(3)
C = area of shaded region
C = A - B
C = 12pi - 9*sqrt(3) .... exact area
C = 22.1106545749577 ... use a calculator to get the approximate area
Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Since there are a total of 4,200 residents and the question is asking for the amount in the south region, take the distribution number from the chart, 0.16, and multiply it by 4,200.
4200 ×.16 = 672
672 residents
