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MatroZZZ [7]
3 years ago
5

How would you write the expression the product 18 and a number b?

Mathematics
1 answer:
mina [271]3 years ago
6 0
Subtraction: 18 - b
Addition: 18 + b
Multiplication: 18b, or 18 x b
Division: 18 divided (My keyboard doesn't have a division sign?) by b
Hope this helped.
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A kite flier wondered how high her kite was flying. She used a protractor to measure an angle of 15∘ from level ground to the ki
Nataly [62]

Answer:

12.9 yd

Step-by-step explanation:

It helps if you draw a triangle. Draw a horizontal segment. That is the ground. Now at the left end start a new segment that goes up to the right at approximately 15 degrees until it its other endpoint directly above the right endpoint of the horizontal segment. Connect these two endpoints. The vertical side on the right shows the height of the kite. The hypotenuse is the string.

For the 15-deg angle, the height of the triangle is the opposite leg, and the string is the hypotenuse. The trig ratio that relates the opposite leg tot he hypotenuse is the sine.

\sin A = \dfrac{opp}{hyp}

\sin 15^\circ = \dfrac{h}{50~yd}

(50~yd)\sin 15^\circ = h

h = (50~yd)(0.2588)

h = 12.9~yd

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2 years ago
If f(x)=x-1/3 and g(x)=3x+1, what is (f o g)(x)?
BlackZzzverrR [31]

Answer:

\[3x+\frac{2}{3}\]

Step-by-step explanation:

\[f(x)=x-\frac{1}{3}\]

\[g(x)=3x+1\]

Hence, \[(f o g)(x)=f(3x+1)\]

But, \[f(3x+1)=(3x+1)-\frac{1}{3}\]

Simplifying,

\[f(3x+1)=3x+(1-\frac{1}{3})\]

= \[f(3x+1)=3x+(\frac{3-1}{3})\]

= \[f(3x+1)=3x+(\frac{2}{3})\]

Hence, \[(f o g)(x)=3x+(\frac{2}{3})\]

8 0
3 years ago
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Answer:

Figure 1: complementary

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Step-by-step explanation:

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Can you subtract closed polynomials
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Answer:

Polynomials are closed under addition. When subtracting polynomials, the variables and their exponents do not change. Only their coefficients will possibly change. This guarantees that the difference has variables and exponents which are already classified as belonging to polynomials.

Step-by-step explanation:

3 0
3 years ago
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