Answer:
We conclude that the percentage of blue candies is equal to 29%.
Step-by-step explanation:
We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.
Let p = <u><em>population percentage of blue candies</em></u>
So, Null Hypothesis,  : p = 29%     {means that the percentage of blue candies is equal to 29%}
 : p = 29%     {means that the percentage of blue candies is equal to 29%}
Alternate Hypothesis,  : p
 : p  29%     {means that the percentage of blue candies is different from 29%}
 29%     {means that the percentage of blue candies is different from 29%}
The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;
                          T.S.  =   ~ N(0,1)
  ~ N(0,1)
where,  = sample proportion of blue coloured candies = 28%
 = sample proportion of blue coloured candies = 28%
            n = sample of colored candies = 100
So, <u><em>the test statistics</em></u> =  
                                     =  -0.22
The value of the z-test statistics is -0.22.
<u>Also, the P-value of the test statistics is given by;</u>
                P-value = P(Z < -0.22) = 1 - P(Z  0.22)
 0.22)
                             = 1 - 0.5871 = 0.4129
Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.
Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.
Therefore, we conclude that the percentage of blue candies is equal to 29%.