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nordsb [41]
2 years ago
10

Anyone know how to do number 2 in stuck please help

Mathematics
1 answer:
solmaris [256]2 years ago
8 0
12/3=4
4*2000=8000

8000mg
my best guess
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Which situation could not be represented by the inequality below:
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Factor 2x^2 + 14x + 12
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2(x+6)(x+1)

2x^2 + 14x + 12
2(x^2 + 7x + 6)
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Basically thats it
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In 1950, scientists estimated a certain animal population in a particular geographical area to be 6,400. In 2000, the population
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Step-by-step explanation:

5 0
3 years ago
15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c
solniwko [45]

Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

-f(x)=x^2

To prove that  the function is objective from R to  (0,\infty)

Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

(x_1)^2=(x_2)^2

Cancel power on both side then we get

x_1=x_2

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

3 0
3 years ago
What is the range of the function graphed below?
Akimi4 [234]

Answer:

C.

-  \infty  < y <   \infty

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3 years ago
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