Explanation:
Formula to calculate the electric potential is as follows.
Putting the given values into the above formula as follows.
= ![\frac{9 \times 10^{9}}{0.25}[\frac{-3.3}{\sqrt{2}} + 4.2] \times 10^{-6}](https://tex.z-dn.net/?f=%5Cfrac%7B9%20%5Ctimes%2010%5E%7B9%7D%7D%7B0.25%7D%5B%5Cfrac%7B-3.3%7D%7B%5Csqrt%7B2%7D%7D%20%2B%204.2%5D%20%5Ctimes%2010%5E%7B-6%7D)
= 
Hence, electric potential at point A is .
Now, the electric potential at point B is as follows.
= ![\frac{9 \times 10^{9}}{0.25} [-3.3 + \frac{4.2}{\sqrt{2}}] \times 10^{-6}](https://tex.z-dn.net/?f=%5Cfrac%7B9%20%5Ctimes%2010%5E%7B9%7D%7D%7B0.25%7D%20%5B-3.3%20%2B%20%5Cfrac%7B4.2%7D%7B%5Csqrt%7B2%7D%7D%5D%20%5Ctimes%2010%5E%7B-6%7D)
= 
Hence, electric potential at point B is .
Answer:
both charges will have different potential energies that will depend upon the charge magnitude.
Explanation:
It is given that both the charges are on the same equipotential line which means the potential V at which the two charges are is same.
Now the potential energy of a charge at potential V is given by
q×V where q is the charge value
Thus Higher the charge value for a given value of potential , higher will be the potential energy
Thus the larger charge will have higher potential energy and not the same.
Answer:
a) 
Now we can replace the velocity for t=1.75 s
For t = 3.0 s we have:
b) 
And we can find the positions for the two times required like this:
And now we can replace and we got:
Explanation:
The particle position is given by:
Part a
In order to find the velocity we need to take the first derivate for the position function like this:
Now we can replace the velocity for t=1.75 s
For t = 3.0 s we have:
Part b
For this case we can find the average velocity with the following formula:
And we can find the positions for the two times required like this:
And now we can replace and we got:
1. The problem statement, all variables and given/known data (a) Calculate the disintegration energy when 232/92U decays by alpha emission into 228/90Th. Atomic masses of 232/92U and 228/90Th are 232.037156u and 228.028741u, respectively. (b) For the 232/92U decay in part (a), how much of the disintegration energy will be carried off by the alpha particle? Given: Mass of 4/2He = 4.002603u c^2 = 931.5MeV
2. Relevant equations E=mc^2
3. The attempt at a solution Well for part (a), first I found the difference in the starting masses and the end masses ie, 232.037156u - (228.028741u + 4.002603u) = 0.005812u I then put this into the equation and got 5.413878MeV. I thought this was right until I read part (b) and now I'm starting to think this might be how I'm meant to do that part, not part (a). Could anyone tell me if I'm even on the right track with this question or should I be using different equations?
