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exis [7]
3 years ago
9

a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh

at is a centripetal force on the car
Physics
1 answer:
Viefleur [7K]3 years ago
5 0
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing.  Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

             F = (mass) · (speed)² / (radius).

For this particular car, the force is

                    (2,000 kg) · (25 m/s)² / (80 m)

                 = (2,000 kg) · (625 m²/s²) / (80 m)

                 = (2,000 · 625 / 80)  (kg · m / s²)

                 =              15,625  newtons .
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During a race, a runner runs at a speed of 6 m/s. Four seconds later, she is running at a speed of 10 m/s. what is the runners a
Georgia [21]
<span>a = (v2 - v1)/t = (10 - 6)/2 = 2 m/sec/sec (average acceleration)</span>
8 0
3 years ago
Plz help me with my PE class
andrew-mc [135]

Answer:

The answer to the first one is, group 1.

Explanation:

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5 0
3 years ago
What is the frequency of a wave that has a speed of 0.6 m/s and a wavelength of 0.020 meter?
UNO [17]
The formula for wave motion is speed of wave equals frequency times wavelength.v = f lambdarearrangingf = v/lambdaf = 0.6/0.02 = 60/2 = 30Hz, or cycles per second.
7 0
3 years ago
A 2.9-kg cart is rolling across a frictionless, horizontal track toward a 1.4-kg cart that is held initially at rest. The carts
VikaD [51]

Answer:

The question is incomplete. I will assume you intend to find the total momentum of the two carts during collision. Therefore, we can use the conservation of momentum principle to get the total momentum at a certain instant before collision.

Explanation:

The conservation of momentum principle states that the initial net momentum of two bodies before collision is equal to the final net momentum after collision.

In this case, let's denote the rolling cart as <em>'a'</em> and the stationary cart as <em>'b'</em>.

Momentum, P = MaVa +MbVb

P=(2.9)(+4.7) + (1.4)(-1.9)\\P= 13.68 + (-2.66)\\P= 13.68-2.66\\P=+11.02 Kg.m/s

Therefore, the total momentum before collision is 11.02 Kg.m/s.

6 0
3 years ago
Both a 3 kg book and 5 kg bowling ball are sitting still on the floor. What is true about the kinetic energy of the objects? Exp
Charra [1.4K]

Answer:

The kinetic energy for both objects is the same.

Explanation:

While in other cases the kinetic energies of two objects that have different masses might be different depending on their velocities, in this case both the 3 kg book and 5 kg bowling ball have the same kinetic energy.

This is because kinetic energy is calculated using the formula: K = 1/2 * m * v^2, where m represents the mass and v represents the velocity of the object.

Since the book and the bowling ball are sitting still on the floor, their velocities are zero.  Hence, when we plug in 0 for velocity into the equation for kinetic energy, we will get that the kinetic energy is 0 for the book and the bowling ball.

Hope this helps!

6 0
3 years ago
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