Answer
Given,
Energy absorbed, 
Energy expels,
Temperature of cold reservoir, T = 27°C
a) Efficiency of engine



b) Work done by the engine



c) Power output
t = 0.296 s



Answer:
C) T
Explanation:
= Mass attached to an ideal spring
= Amplitude of the motion
= Time period of oscillation
= Spring constant of the spring
= Amplitude of the motion
Time period of oscillation of the mass attached to the spring is given as

So we see that the time period does not depend on the amplitude. hence the period of oscillation remains the same.
Answer:
376966.991 Joules
Explanation:
Given that :
the height = 12 m
Let assume the tank have a thickness = dh
The radius of the tank by using the concept of similar triangle is :


The area of the tank =
The area of the tank = 
The area of the tank = 
The volume of the tank is = area × thickness
= 
Weight of the element = 
where;
= density of water ; which is given as 10000 N/m³
So;
Weight of the element = 
Weight of the element = 
However; the work required to pump this water = weight × height rise
where the height rise = 12 - h
the work required to pump this water =
(12 - h)
the work required to pump this water = 
We can determine the total workdone by integrating the work required to pump this water
SO;
Workdone = 
= 
= ![\mathbf{ 69.44 \pi[ \frac{12h^3}{3}- \frac{h^4}{4}]^{12}}_0} }](https://tex.z-dn.net/?f=%5Cmathbf%7B%2069.44%20%5Cpi%5B%20%5Cfrac%7B12h%5E3%7D%7B3%7D-%20%20%5Cfrac%7Bh%5E4%7D%7B4%7D%5D%5E%7B12%7D%7D_0%7D%20%7D)
= ![\mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B69.44%20%5Cpi%20%5B%20%5Cfrac%7B12%5E4%7D%7B3%7D-%5Cfrac%7B12%5E4%7D%7B4%7D%5D%7D)
= ![\mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B69.44%20%5Cpi%2A12%5E4%20%5B%20%5Cfrac%7B4-3%7D%7B12%7D%5D%7D)
= 
= 376966.991 Joules
I am 99999.999999999% sure that it is his second law of motion.
Hope this helped! :) Please mark brainliest