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3 years ago

What is 10 3/17 as a improper fraction

Mathematics

2 answers:

tatiyna3 years ago

8 0

Answer:

the answer is 173/7

hope this helps

jeyben [28]3 years ago

6 0

Answer:

To convert mixed number 10 3/17 to improper fraction, you follow these steps:

First, note that 10 3/17 is a mixed number, also know as mixed fraction. It has a whole number and a proper fraction. The numbers in the mixed fraction are defined as follow:

10 = whole number

3 = numerator

17 = denominator

Multiply the whole number by the denominator

10 × 17 = 170

Add the product from Step 1 to the numerator

170 + 3 = 173

Write answer from Step 2 over the denominator

173/17

The mixed number 10 3/17 converted to improper fraction is therefore :

173/17

Step-by-step explanation:

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AURORKA [14]

Answer:

25% of probabilities

Step-by-step explanation:

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4 0

3 years ago

How to solve 5h+7=17

Alex777 [14]

If you are trying to find h, then its very simple.
So lets see 5+7=12
So 17-12=5
So lets check to see if h=5
5+5+7
5+5=10+7=17 so h is 5. :)

5 0

3 years ago

Find the probability of winning a lottery by selecting the correct six integers, where the order in which these inte

stich3 [128]

The probability of winning a lottery by selecting the correct six integers, are

$\begin{aligned}&(a) 1.68 \times 10^{-6} \\&(b) 5.13 \times 10^{-7} \\& (c) 1.91 \times 10^{-7} \\&(d)8.15 \times 10^{-8}\end{aligned}$

<h3>What is binomial distribution?</h3>

The binomial distribution is a type of probability distribution that expresses the probability that, given a certain set of characteristics or assumptions, a value would take one of two distinct values.

Part (a); positive integers not exceeding 30.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other twenty-four.

$\frac{\left(\begin{array}{c}6 \\6\end{array}\right)\left(\begin{array}{c}24 \\0\end{array}\right)}{\left(\begin{array}{c}30 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}30 \\6\end{array}\right)}=1.68 \times 10^{-6}$

Part (b); positive integers not exceeding 36.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other thirty.

$\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}30 \\0\end{array}\right)}{\left(\begin{array}{c}36 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}36 \\6\end{array}\right)}=5.13 \times 10^{-7}$

Part (c); positive integers not exceeding 42.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the 36 other integers.

$\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}36 \\0\end{array}\right)}{\left(\begin{array}{c}42 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}42 \\6\end{array}\right)}=1.91 \times 10^{-7}$

Part (d); positive integers not exceeding 48.

To calculate the probability, use binomial coefficients. Choose six of the six accurate integers and none of the other 42.

$\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}42 \\0\end{array}\right)}{\left(\begin{array}{c}48 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}48 \\6\end{array}\right)}=8.15 \times 10^{-8}$

To know more about binomial probability, here

brainly.com/question/9325204

#SPJ4

The complete question is-

Find the probability of winning a lottery by selecting the correct six integers, where the order in which these integers are selected does not matter, from the positive integers not exceeding a) 30. b) 36. c) 42. d) 48.

5 0

2 years ago

What is <br> 1 + 1<br> 2 + 2 <br> 4 + 4<br> 8 + 8<br> 16 + 16<br> Btw chat room for all!!

DENIUS [597]

OH i know this one! i know this one!!

* grabs my notebook and a pencil and lays on the floor* hm... its

yay!! lol this was me lol