To find the area of any regular (regular means all sides are = and all angles are =) poylgon when you know the length of the apothem and the length of the side you can use the formula:
A = (1/2)ap where a = the length of the apothem and p = the perimeter of the polygon. You can also use n*s in place of p where n = the number of sides of the polygon and s = the length of the side.
A= (1/2)(16)(19*8) (An octagon has 8 sides.)
A = 1216 in^2
Answer: there is no picture attached or equation? what's the question?
Step-by-step explanation:
If you're asking how, here's an example
A standard form equation is when it is set up.
Ax + By = C.
6x + 2y = 4.
A slope-intercept form equation is when it is set up y=mx+b.
Y = - 3x + 2.
4y = -8x + 16 then divide all by 4.
y = -2x + 4 slope form.
Answer:
Option (d).
Step-by-step explanation:
Note: The base of log is missing in h(x).
Consider the given functions are
The function m(x) can be written as
...(1)
The translation is defined as
.... (2)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
On comparing (1) and (2), we get
Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).
Hence, option (d) is correct.
Answer:
the number is 8 andequation is 3x-5=19
