A substance that dissolves in water is said to be

By paying low wages, factory owners were able to

sweet [91]

To make more profit and make their business/company’s lager this also means that the customers that buy products have more variety of choices

5 0

4 years ago

A mixture of A and B is capable of being ignited only if the mole percent of A is 6 %. A mixture containing 9.0 mole% A in B flo

atroni [7]

Explanation:

As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.

Hence, calculate the molecular weight of the mixture as follows.

Weight = $0.09 \times 16.04 + 0.91 \times 29$

= 27.8336 g/mol

And, molar flow rate of air and mixture is calculated as follows.

$\frac{800}{27.8336}$

= 28.74 kmol/hr

Now, applying component balance as follows.

$0.09 \times 28.74 + 0 \times F_{B} = 0.06F_{p}$

$F_{p}$ = 43.11 kmol/hr

$F_{A} + F_{B} = F_{p}$

$F_{B}$ = 43.11 - 28.74

= 14.37 kmol/hr

So, mass flow rate of pure (B), is $F_{B}$ = $14.37 \times 29$

= 416.73 kg/hr

According to the product stream, 6 mol% A and 94 mol% B is there.

Molecular weight of product stream = $Mol. weight \times 43.11 kmol/hr$

= $0.06 \times 16.04 + 0.94 \times 29$

= 28.22 g/mol

Mass of product stream = 1216.67 kg/hr

Hence, mole of $O_{2}$ into the product stream is as follows.

$0.21 \times 0.94 \times 43.11$

= $8.5099 kmol/hr \times 329 g/mol$

= 272.31 kg/hr

Therefore, calculate the mass % of $O_{2}$ into the stream as follows.

$\frac{272.31}{1216.67} \times 100$

= 22.38%

Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of $O_{2}$ in the product gas is 22.38%.

4 0

3 years ago

Can you help me with these 5 questions 5 pts each

Alenkasestr [34]

The ampere (A) The ampere is the SI base unit of electrical current. ...The candela (cd) The candela is the SI base unit of luminous intensity. ...The kelvin (K) The kelvin is the SI base unit of thermodynamic temperature. ...The kilogram (kg) The kilogram is the SI base unit of mass. ...The metre (m) ...The mole (mol) ...The second (s)

7 0

4 years ago

A helium balloon has a volume of 36 L. The pressure of the helium gas in the balloon is 132 kPa and its temperature is 27 degree

Verdich [7]

Answer:

$n =1.905mol$

Explanation:

Hello!

In this case, by considering helium gas as an ideal one, we can use the following equation:

$PV=nRT$

Whereas P should go in atmospheres and T in Kelvins; thus we proceed as follows:

$n=\frac{PV}{RT}=\frac{132kPa*\frac{1atm}{101.325kPa}*36L}{0.08206\frac{atm*L}{mol*K}(27+273)K} =1.905mol$

Best regards!

3 0

3 years ago

Why is the presence of granite critical for the formation of MT. Lico

kiruha [24]

<h2><u>Answer:</u></h2>

Lico. The stone was unclear range from the including territory. Between 130 million and 500 million years back, magma from volcanoes cooled to shape the stone that would advance toward getting to be Mt.

On Mount Lico in northern Mozambique is a site that few have had the enjoyment of seeing – a hid rainforest, verified by an unsafe float of shake. In spite of the way that the mountain was known to neighborhood individuals, the forested areas itself remained a secret until six years back, when Julian Bayliss spotted it on satellite imagery.

5 0

3 years ago

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