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3 years ago

Using equations so that aluminium oxide is amphoteric

Chemistry

1 answer:

snow_tiger [21]3 years ago

7 0

Answer:

Amphoteric metal oxides react with both acids as well as bases to produce salt and water.

Aluminium oxide is an amphoteric oxide because it reacts with acids as well as bases and form salts and water.

Al2O3 + 6HCl → 2AlCl3 + 3H2O (Basic nature)

Aluminium Hydrochloric Aluminium Water.

oxide acid chloride.

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What compounds break up into ions solution?

Korolek [52]

Answer:

Acids are compounds that dissociate (break) into hydrogen (H+) ions and another compound when placed in an aqueous solution.

Explanation:

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3 years ago

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A syringe containing 1.63 mL of oxygen gas is cooled from 91.0 ∘C to 0.9 ∘C. What is the final volume Vf of oxygen gas? (Assume

Archy [21]

Answer:

Vf = 1.22 mL

Explanation:

If we assume that the pressure is constant and the number of moles does not change, we can say that the volume of the gas is modified in a directly ratio, to the Absolute Temperature.

Let's convert the values:

91°C + 273 = 364K

0.9°C + 273 = 273.9K

Volume decreases if the temperature is decreases

Volume increases if the T° increases

V₁ / T₁ = V₂ / T₂ → 1.63mL /364K = V₂ / 273.9K

V₂ = (1.63mL /364K) . 273.9K → 1.22 mL

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4 years ago

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How many moles of carbon dioxide are produced when 5.12 moles of glucose undergoes a combustion reaction?

SVEN [57.7K]

Answer: 30.72 moles of $CO_2$ will be produced from 5.12 moles of glucose.

Explanation:

The balanced chemical equation for combustion of glucose is:

$C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O$

According to stoichiometry :

1 moles of glucose produce = 6 moles of $CO_2$

Thus 5.12 moles of glucose produce = $\frac{6}{1}\times 5.12=30.72moles$ of $CO_2$

Thus 30.72 moles of $CO_2$ will be produced from 5.12 moles of glucose.

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3 years ago

A 20g sample of iron at a temperature of 120oC is placed into a container of water. There are 300 milliliters of water in the co

galben [10]

Answer:

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of iron = $m_1=20 g$

Specific heat capacity of iron = $c_1=0.444 J/g^oC$

Initial temperature of the iron = $T_1=120^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water= $m_2=300 mL\times 1 g/mL = 300 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=30^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

we get, T = 30.63°C

30.63 °C will be the final temperature of the water.

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3 years ago

Which rock composed of a mineral that can be used for the production of cement?

Kamila [148]

I believe the answer is Limestone
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4 years ago

Using equations so that aluminium oxide is amphoteric ​

Using equations so that aluminium oxide is amphoteric