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Anni [7]
3 years ago
11

Does dilution reduce the amount of conductivity?

Chemistry
1 answer:
lukranit [14]3 years ago
4 0

Answer:

yes

Explanation:

dilution can reduce the amount of conductivity

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re clear. Try to convey your meaning as simply as possible. Don't over-write or use exorbitant language. ...

Are complete. Include all relevant information. Think about the situation from your readers' perspective. ...

Are correct. Always proofread before sending any message.

Explanation:

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HELP ASAP !!!!!
Anna35 [415]

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Explanation:

Take a random sample of nuts from the jar.  Let's take two handfuls, after shaking the jar and mixing the nuts thoroughly.  Separate the nuts into almonds and cashews.  Count each pile, then do the following calculation (these numbers are random, for example only).

                <u> Count</u>   <u>Percentage %</u>

Almonds       38        (38)/(87)x100

Cashews      <u> 49</u>         49/87x100

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Ratio of Almonds to Cashews:  <u>38/49</u>

3 0
3 years ago
Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: h2co3+h2o?hco3?+h3o+ identify the conjugate acid-b
Levart [38]
Conjugate base pairs are acid and bases having common features. These features are the equal gain or loss of protons of the pairs. Conjugate pairs should always be one base and one acid. One would not exist without the other. Conjugate acids are the substances that gains protons while conjugates bases are those that loses protons. <span>The substances in the equilibrium reaction that is given is identified as follows: 
HCO3^-      +     H2O <----->   CO3^2-          +             H3O^+ 
 acid                   base         conjugate base           conjugate acid 

HCO3^- ion is an intermediate molecule of CO2 and CO3^2-. When we add OH- to HCO3^-, we produce CO3^2-. And when we add H+ to HCO3, we produce CO2. </span>
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3 years ago
Using the diagram below, which rock layer is older than the Chinle Formation?
Klio2033 [76]

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Explanation:

also pls mark brainliest <3 :)))

3 0
3 years ago
if i add 25 ml of water to 135 ml of a 0.25 M NaOH solution what will the molarity of the diluted solution be​
DENIUS [597]

Answer:

0.21 M. (2 sig. fig.)

Explanation:

The molarity of a solution is the number of moles of the solute in each liter of the solution. The unit for molarity is M. One M equals to one mole per liter.

How many moles of NaOH in the original solution?

n = c \cdot V,

where

  • n is the number of moles of the solute in the solution.
  • c is the concentration of the solution. c = 0.25 \;\text{M} = 0.25\;\text{mol}\cdot\textbf{L}^{-1} for the initial solution.
  • V is the volume of the solution. For the initial solution, V = 135\;\textbf{mL} = 0.135\;\textbf{L} for the initial solution.

n = c\cdot V = 0.25\;\text{mol}\cdot\textbf{L}^{-1} \times 0.135\;\textbf{L} = 0.03375\;\text{mol}.

What's the concentration of the diluted solution?

\displaystyle c = \frac{n}{V}.

  • n is the number of solute in the solution. Diluting the solution does not influence the value of n. n = 0.03375\;\text{mol} for the diluted solution.
  • Volume of the diluted solution: 25\;\text{mL} + 135\;\text{mL}  = 160\;\textbf{mL} = 0.160\;\textbf{L}.

Concentration of the diluted solution:

\displaystyle c = \frac{n}{V} = \frac{0.03375\;\text{mol}}{0.160\;\textbf{L}} = 0.021\;\text{mol}\cdot\textbf{L}^{-1} = 0.021\;\text{M}.

The least significant number in the question comes with 2 sig. fig. Keep more sig. fig. than that in calculations but round the final result to 2 sig. fig. Hence the result: 0.021 M.

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3 years ago
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