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sergey [27]
3 years ago
14

What is a real life word problem for the equation y=2x Will give brainliest

Mathematics
1 answer:
hammer [34]3 years ago
5 0

Answer:

y = 2x

Step-by-step explanation:

Claire is hungry. She buys 2 donuts each costing x $. How much should she pay?

Since one donut costs x $ 2 donuts cost 2x $.

Therefore, total amount Claire should pay, call it y = 2x

Hence, we have y = 2x.

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You are selling lemonade for $1.50,a bag of kettle corn for $3,and a hot dog for $2.50 at a fair .write and simplify an expressi
Sergio [31]
<h2>When you sell these three things you would need 3 people (p) to buy them. But together or separate.</h2><h2 /><h2>$1.50 + $3.00+$2.50= $7.00</h2>


6 0
4 years ago
Which set of measurements could be the side lengths of a triangle?
Artist 52 [7]
We know that
Triangle Inequality Theorem establishes that the sum of the lengths of any two sides of a triangle<span> is greater than the length of the third side
</span>so
case <span>A. 5M, 11M, 7M
5+11 > 7----> ok
11+7 > 5 ---> ok
5+7 > 11----> ok

case </span><span>B.10 m, 4 m, 5 m
5+4 > 10-----> is not ok

case </span><span>C.8 m, 4 m, 4 m
4+4 > 8----> is not ok

case </span><span>D.6 m,11 m, 5 m
6+5 > 11-----> is not ok

the answer is
</span><span>A. 5M, 11M, 7M</span>
6 0
3 years ago
Which number has the same value
photoshop1234 [79]
Answer:
D 0.08

Explanation:
dunno how to
7 0
4 years ago
A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng
tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, xy \leq 8000

So,x(220-x) \leq 8000

220x-x^2 \leq 8000

So,220x-x^2 = 8000\\-x^2+220x-8000=0

General quadratic equation : ax^2+bx+c=0

Formula : x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0
3 years ago
Solve for the indicated variable.
marta [7]

Answer:

Option (c) "r=\dfrac{q}{4c}-h"

Step-by-step explanation:

The given equation is :

q = c4(h + r)

We need to solve it for r.

Dividing both sides of the given equation by 4c.

\dfrac{q}{4c}=\dfrac{4c}{4c}(h+r)\\\\(h+r)=\dfrac{q}{4c}

Now, subtract h both sides of the equation.

h+r-h=\dfrac{q}{4c}-h\\\\r=\dfrac{q}{4c}-h

Hence, this is the required solution.

3 0
3 years ago
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