Question

An airliner lands with a speed of 50.0 m/s. Each wheelof the

Answer 1

Answer:

0.52378

Explanation:

V = Velocity = 50 m/s

r = Radius = 1.25 m

I = Moment of inertia = 110 kgm²

N = Weight supported by wheels = 14000 N

The angular velocity

$\omega=\dfrac{V}{r}\\\Rightarrow \omega=\dfrac{50}{1.25}\\\Rightarrow \omega=40\ rad/s$

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{40-0}{0.48}\\\Rightarrow \alpha=83.33\ rad/s^2$

Frictional force is given by

$f=\dfrac{I\alpha}{r}\\\Rightarrow f=\dfrac{110\times 83.33}{1.25}\\\Rightarrow f=7333.04\ N$

The coefficient of friction is given by

$\mu=\dfrac{f}{N}\\\Rightarrow \mu=\dfrac{7333.039}{14000}\\\Rightarrow \mu=0.52378$

The coefficient of friction is 0.52378