If they're brought closer together
Answer:
Mercury is a bad conductor of heat but a fair conductor of electricity
By the way PURE SILVER is the best conductor of electricity
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Forced-Air would be the type of central heating system
Answer:
6400 m
Explanation:
You need to use the bulk modulus, K:
K = ρ dP/dρ
where ρ is density and P is pressure
Since ρ is changing by very little, we can say:
K ≈ ρ ΔP/Δρ
Therefore, solving for ΔP:
ΔP = K Δρ / ρ
We can calculate K from Young's modulus (E) and Poisson's ratio (ν):
K = E / (3 (1 - 2ν))
Substituting:
ΔP = E / (3 (1 - 2ν)) (Δρ / ρ)
Before compression:
ρ = m / V
After compression:
ρ+Δρ = m / (V - 0.001 V)
ρ+Δρ = m / (0.999 V)
ρ+Δρ = ρ / 0.999
1 + (Δρ/ρ) = 1 / 0.999
Δρ/ρ = (1 / 0.999) - 1
Δρ/ρ = 0.001 / 0.999
Given:
E = 69 GPa = 69×10⁹ Pa
ν = 0.32
ΔP = 69×10⁹ Pa / (3 (1 - 2×0.32)) (0.001/0.999)
ΔP = 64.0×10⁶ Pa
If we assume seawater density is constant at 1027 kg/m³, then:
ρgh = P
(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa
h = 6350 m
Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.
Answer:
(a)
(b)
Explanation:
<u>Given:</u>
- = The first temperature of air inside the tire =
- = The second temperature of air inside the tire =
- = The third temperature of air inside the tire =
- = The first volume of air inside the tire
- = The second volume of air inside the tire =
- = The third volume of air inside the tire =
- = The first pressure of air inside the tire =
<u>Assume:</u>
- = The second pressure of air inside the tire
- = The third pressure of air inside the tire
- n = number of moles of air
Since the amount pof air inside the tire remains the same, this means the number of moles of air in the tire will remain constant.
Using ideal gas equation, we have
Part (a):
Using the above equation for this part of compression in the air, we have
Hence, the pressure in the tire after the compression is .
Part (b):
Again using the equation for this part for the air, we have
Hence, the pressure in the tire after the car i driven at high speed is .