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Pepsi [2]
3 years ago
8

 5) You did 170 joules of work lifting a 140 N backpack. How high did you lift the backpack?          

Physics
2 answers:
love history [14]3 years ago
7 0

Answer:

d = 1.21 meters

The mass of the backpack is 31.48 pound.

Explanation:

(5) Work done in lifting a backpack, W = 170 J

The force acting on the backpack, F = 140 N

The work done by an object is given by :

W=F\times d

d is the height at which the backpack is lifted

d=\dfrac{W}{F}

d=\dfrac{170\ J}{140\ N}

d = 1.21 meters

So, the backpack is lifted to a height of 1.21 meters.

(6) If m is the mass of the backpack. It can be calculated as :

W = mg

m=\dfrac{W}{g}

m=\dfrac{140}{9.8}

m = 14.28 kg

Since, 1 kg = 2.204 pound

14.28 kg = 31.48 pound

So, the mass of the backpack is 31.48 pound. Hence, this is the required solution.

xeze [42]3 years ago
5 0
Sorry im from the UK, ill do my math in metric  :) 
5) work done = force * distance moved in direction of force

170J = 140N* ?d
170J/140N = 1.21m 

F=Ma

140N/9.81ms^-2=

14.27Kg or 31.46Ib

you could do the fast alternative simplified route to this question 

as 140/4.45 = 31.46Ib

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olga55 [171]

Answer:

Input force of pulley system = 200 N

Explanation:

Given:

Mechanical advantage of pulley system = 5

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Computation:

Mechanical advantage = Output force / Input force

Mechanical advantage of pulley system = Output force from pulley system / Input force of pulley system

5 = 1,000 / Input force of pulley system

Input force of pulley system = 1,000 / 5

Input force of pulley system = 200 N

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IceJOKER [234]

Answer:

0.72 Hz minimum frequency

Explanation:

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here \omega _{o}^{2}= k/m = (6.30)/(0.135) = 46.67 N/m kg

F / mA = 1.70/(0.135)(0.480) = 26.2 N/m kg

From the above equation , rearranging for ω,

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⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47

⇒ ω = 8.53 or 4.52 rad/s

Frequency = f

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⇒ f = ω / 2π =  8.53 /6.28  or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz

The lower frequency is 0.72 Hz and higher is 1.36 Hz

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In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
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Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

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Therefore, the distance between the two spheres is 914.41 X 10³ m

3 0
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