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Mashutka [201]
3 years ago
14

A large grocery store received an order of 2 thousand apples. A neighboring school received an order of 20 boxes of apples with

100 apples In each. Use disks or disks on a place value chart to compare the number of apples received by the school and the number of apples received by the grocery store

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Total number of apples received by a large grocery store = 2 thousand apples

= 2000 apples.

Total number of boxes of apples received by  a neighboring school = 20 boxes

Number of apples in each box = 100 apples

Therefore, the total number of apples received by neighboring school

= 20 \times 100

= 2000 apples.

Refer to the image for place value disk chart.

Hence, the number of apples received by the school and the number of apples received by the grocery store are equal.

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Answer:

The answer is

y = 6x + 43

Step-by-step explanation:

Equation of a line is y = mx + c

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To find the equation of the parallel line we must first find the slope of the original line

The original line is y = 6x + 1

Comparing with the general equation above

Slope = 6

Since the lines are parallel their slope are also the same

Slope of parallel line = 6

The equation of the line using point (-7,1) and slope 6 is

We have the final answer as

y = 6x + 43

Step-by-step explanation:

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enson is picking out what to wear to school. He has three clean T-shirts: one white, one red, and one orange. He also has two cl
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The missing color is D. white.
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Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
Veronika [31]

Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

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