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OlgaM077 [116]
3 years ago
14

Mr. Paulsen challenges Olivia and Angelica to move figure ABCDE onto figure A"B"C"D"E" using a series of two different transform

ations. They give two different answers.
Answer the questions to investigate ways to transform ABCDE.

1. Olivia finds a combination of two different transformations that moves ABCDE onto A"B"C"D"E". What is one way she might have done this?

2. Angelica reflects ABCDE over the y-axis and translates it up 8 units. Does her transformed figure match A"B"C"D"E"? If not, describe how her transformed figure compares to A"B"C"D"E".

3. Michael says he can move ABCDE onto A"B"C"D"E" with one transformation by translating ABCDE diagonally so that it moves 8 units up and 10 units right. Is he correct? Explain why or why not.

Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

Problem 1

One method Olivia could have used is to reflect over the x axis and then translate 10 units to the right.

Let's apply these set of steps to point C.

C = (-2,-4)

C' = (-2,4) after reflecting over the x axis; y coordinate flips in sign

C'' = (8,4) after shifting to the right 10 units; add 10 to the x coordinate

Point C(-2,-4) moves to C''(8,4) which is shown in the diagram. I'll let you check the other four points.

-----------

Another method Olivia could have used is to shift to the right 10 units first, then reflect over the x axis. In this case, the order doesn't matter. Though for some other combinations of transformations, order does matter.

============================================================

Problem 2

Reflecting over the y axis will have the point (x,y) turn into (-x,y). Only the x coordinate changes, and we flip the sign here. The y coordinate stays the same.

A point like C(-2,-4) becomes C'(2,-4) after the y axis reflection. Shifting up 8 units means we add 8 to the y coordinate to arrive at C''(2,4) but this does not match what the diagram shows. Therefore, Angelica's method is incorrect.

You should find other inconsistencies for the other four points as well.

============================================================

Problem 3

Michael's method isn't correct either. He does not apply an x axis reflection and instead relies entirely on translations to move ABCDE to A''B''C''D''E''

At a quick glance, it looks like Michael may be correct. But upon a much closer look, you'll see that things don't line up perfectly.

Instead of point C, we'll pick on point D this time.

D is located at (-6,-2). If we shift up 8 units, then we add 8 to the y coordinate to get to D'(-6,6). Then add 10 to the x coordinate to shift 10 units to the right. This leads us to D''(4,6).

However, the diagram shows D'' is actually at (4,2)

I'll let you check the other points. You should find that only points C and E go to the correct locations, but the other points do not. Again, this is because Michael did not apply an x axis reflection. His figure of A''B''C''D''E'' is upside down compared to what it should be.

============================================================

To summarize, the methods described in problem 1 are the correct way to get ABCDE to move to A''B''C''D''E''. If Olivia followed either of those two methods, then she is correct. Both Angelica and Michael have incorrect methods.

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
sashaice [31]

Answer:

k = –10

Step-by-step explanation:

From the question given above, the following data were obtained:

f(x) = x³ – 6x² – 11x + k

Factor => x + 2

Value of K =?

Next, we shall obtained the value of x from x + 2. This is illustrated below:

x + 2 = 0

Collect like terms

x = 0 – 2

x = –2

Finally, we shall determine the value of k as illustrated below:

f(x) = x³ – 6x² – 11x + k

x = –2

Thus,

f(–2) = 0

x³ – 6x² – 11x + k = 0

(–2)³ – (–2)² – 11(–2) + k = 0

–8 – (4) + 22 + K = 0

–8 – 4 + 22 + K = 0

10 + k = 0

Collect like terms

k = 0 – 10

k = –10

Thus, the value of k is –10

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3 years ago
he​ half-life for a link on a social network website is 2.6 hours. Write an exponential function T that gives the percentage of
pychu [463]

Answer:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining= [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

Step-by-step explanation:

Previous concepts

The half-life is defined "as the amount of time it takes a given quantity to decrease to half of its initial value. The term is most commonly used in relation to atoms undergoing radioactive decay, but can be used to describe other types of decay, whether exponential or not".

Solution to the problem

The half life model is given by the following expression:

A(t) = A_o (1/2)^{\frac{t}{h}}

Where A(t) represent the amount after t hours.

A_o represent the initial amount

t the number of hours

h=2.6 hours the half life

And we want to estimate the % after 5.5 hours. On this case we can begin finding the amount after 5.5 hours like this:

A(5.5) = A_o (1/2)^{\frac{5.5}{2.6}}

Now in order to find the percentage relative to the initial amount w can use the definition of relative change like this:

% Remaining = \frac{|A_o - A_o(1/2)^{\frac{5.5}{2.6}}|}{A_o} x100

We can take common factor A_o and we got:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining = [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

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3 years ago
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laiz [17]
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3 years ago
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arsen [322]
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3 years ago
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Artyom0805 [142]

Answer:

Alright, the answer to the equation -52+3= -49

Step-by-step explanation:

I don't know how the heck Marcus and Jeremy got -22 and 28 but both are wrong. If there were a picture so I could see their work, I would be able to figure it out.

Anyways, The math is:

-52 + 3 which is pretty much 52-3 and then the answer has a negative sign.

-52 goes up 3 because technically the negative sign is down. Counting up 3 from 52 equals -49.

6 0
3 years ago
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