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vampirchik [111]
3 years ago
13

If the area of a square sandbox is 64 square meters, which is closest to the length of the diagonal of the sandbox? F 8 m G 9 m

H 10 m J 11 m​
Mathematics
1 answer:
Ivanshal [37]3 years ago
7 0

Answer:

Step-by-step explanation:

A=s^2=64

s=8m

d^2=x^2+y^2, since it is a square x=y=8 then

d^2=2x^2

d^2=2(8^2)

d^2=128

d=11.3

So diagonal is approximately 11m

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Plz help i need it bad
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Answer:

See below

Step-by-step explanation:

Vertices are the black dots of the figure:

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5 0
2 years ago
Read 2 more answers
Suppose the sum of two integers is negative. Must both integers be negative? Explain.
mash [69]

Answer:

Not necessarily. There are many ways to write a basic equation with a negative answer. For example, -3-4 = -7. Here 4 is a positive number but because you subtract 4 to 3 or take away 4 from 3 being a negative number and so you get a negative answer. Another example is 6+(-9). There are a couple of ways you can resolve this. My method is to subtract 9 from 6 which gives you 3 and simply add a negative sign.

Let me know if you'd  like more examples. Hope this helps!! Sorry if it is confusing I can explain you in a more simpler way if you'd like.

Step-by-step explanation:

8 0
2 years ago
A habitat of prairie dogs can support mmm dogs at most.
Sloan [31]

Answer:

The correct answer is p = K × x × (m - p) , where K is the constant of proportionality and x is the current population of the habitat.

Step-by-step explanation:

A habitat of prairie dogs can support m dogs at most.

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3 0
3 years ago
250 in expanded form
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Answer:

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Step-by-step explanation:

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Answer:

<h2>x = 1 - 4i or x = 1 + 4i</h2>

Step-by-step explanation:

x^2-2x+17=0\qquad\text{subtract 17 from both sides}\\\\x^2-2x=-17\\\\x^2-2(x)(1)=-17\qquad\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2(x)(1)+1^2=-17+1^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-1)^2=-17+1\\\\(x-1)^2=-16

x-1=-4i\ \vee\ x-1=4i\qquad\text{add 1 to both sides}\\\\x=1-4i\ \vee\ x=1+4i

4 0
2 years ago
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