Answer:
The order of solubility is AgBr < Ag₂CO₃ < AgCl
Explanation:
The solubility constant give us the molar solubilty of ionic compounds. In general for a compound AB the ksp will be given by:
Ksp = (A) (B) where A and B are the molar solubilities = s² (for compounds with 1:1 ratio).
It follows then that the higher the value of Ksp the greater solubilty of the compound if we are comparing compounds with the same ionic ratios:
Comparing AgBr: Ksp = 5.4 x 10⁻¹³ with AgCl: Ksp = 1.8 x 10⁻¹⁰, AgCl will be more soluble.
Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹² with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of the ratio of ions 2:1 in Ag2CO3, so the answer is not obvious. But since we know that
Ag2CO3 ⇄ 2 Ag⁺ + CO₃²₋
Ksp Ag2CO3 = 2s x s = 2 s² = 8.0 x 10-12
s = 4 x 10⁻12 ∴ s= 2 x 10⁻⁶
And for AgCl
AgCl ⇄ Ag⁺ + Cl⁻
Ksp = s² = 1.8 x 10⁻¹⁰ ∴ s = √ 1.8 x 10⁻¹⁰ = 1.3 x 10⁻⁵
Therefore, AgCl is more soluble than Ag₂CO₃
The order of solubility is AgBr < Ag₂CO₃ < AgCl
An empirical formula is the chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms.
For example the molecule 'CH2O' is the empirical formula for glucose.
It is B. More slowly than a Gas.
Statement D is the correct option as the solution will have pH of 3. It has an H3O+ ion concentration of 1 × mol/L and is acidic.
Explanation:
It is given in question that solution must have pH of 3. The value if being less than 7 shows that solution is acidic. The pH value of 3 indicates that given solution is highly acidic and has strong acid. Strong acid gets fully dissociated into ions.
pH of the solution is calculated as:
pH = -log10[]
the concentration or molarity of the hydronium ion is given as moles/litre
concentration of hydronium ion in the solution is 1 X moles/litre
putting the values in the equation:
pH = - log10( 1 X )
pH = 3 (acidic)
Thus it can be concluded that D option is the right answer.
Answer: ITS D TRUST ME.
Explanation:
I got it right on edge 2021.