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2 years ago

How many g NaOH should be required to completely react 1.876 g of Copper (II) nitrate?

Chemistry

1 answer:

Doss [256]2 years ago

8 0

$\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2$

Moles of copper nitrate:-

$\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol$

1mol of Copper nitrate reacts with 2mol NaOH
0.001mol will react with 0.002mol NaOH

Madd of NaOH

$\\ \tt\hookrightarrow 0.002(40)=0.08g$

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