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Sergeeva-Olga [200]
2 years ago
13

How many g NaOH should be required to completely react 1.876 g of Copper (II) nitrate?

Chemistry
1 answer:
Doss [256]2 years ago
8 0

\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2

Moles of copper nitrate:-

\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol

  • 1mol of Copper nitrate reacts with 2mol NaOH
  • 0.001mol will react with 0.002mol NaOH

Madd of NaOH

\\ \tt\hookrightarrow 0.002(40)=0.08g

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Harlamova29_29 [7]

Given :

Human blood should have around 1.04 kg/L platelets.

A blood sample of 4.01 milliliters is collected from a patient to be analyzed for a platelet count.

To Find :

The expected mass in grams of platelets in the blood sample.

Solution :

1 L of human blood contains 1.04 kg of platelets.

So, amount of platelets is 1 ml blood is :

=\dfrac{1.04}{1000}\ kg\\\\= \dfrac{1.04\times 1000}{1000}\ gram\\\\= 1.04 \ gram

Mass of platelets in 4.01 ml blood is :

m = 1.04\times 4.01\ gram\\\\m = 4.1704\ gram

Hence, this is the required solution.

3 0
3 years ago
C12H22O11 + 11 H2SO4 12 C + 11 H2SO4 + 11 H2O
Vladimir [108]

Answer:

B: The sulfuric acid is not consumed or react with the reactant.

4 0
3 years ago
Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
A 15.0 L tank of gas is contained at a high pressure of 8.20 x 10^4 torr. The tank is opened and the gas expands into an empty c
Inga [223]

Answer:

20.5torr

Explanation:

Given parameters:

V₁  = 15L

P₁  = 8.2 x 10⁴torr

V₂ = 6 x 10⁴L

Unknown:

P₂  = ?

Solution:

To solve this problem we have to apply the claims of Boyle's law.

Boyle's law is given mathematically as;

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where P₁ is the initial pressure

          V₁ is the initial volume

           P₂ is final pressure

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   8.2 x 10⁴  x 15  = P₂  x 6 x 10⁴

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5 0
3 years ago
AN atoms nucleus contains it's protons and electrons true or false
lesantik [10]
True, an atoms nucleus has both protons and electrons.
4 0
2 years ago
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